The loop exits when left > right, and right will point to the last occurrence of the target or the last element smaller than the target if the target is not found. 4. Time & Space Complexity Analysis: Time Complexity: O(logn) Space Complexity: O(1) ...
Given two stringsneedleandhaystack, return the index of the first occurrence ofneedleinhaystack, or-1ifneedleis not part ofhaystack. implSolution{pubfnstr_str(haystack:String,needle:String)->i32{lethlen=haystack.len();letnlen=needle.len();ifhlen<nlen{return-1;}foriin0..=(hlen-nlen){if&...
LeetCode 28: Find the Index of the First Occurrence in a String 心路历程 一开始迅猛完成了一个版本,然后忽略了这种情况 "mississippi" "issip" 这样我会第一个在ssippi第二个在issip这样就找不到了 highlighter- C++ classSolution{public:intstrStr(string haystack, string needle){/* find the first n...
The first occurrence is at index 0, so we return 0. Example 2: Input:haystack = "leetcode", needle = "leeto"Output:-1Explanation:"leeto" did not occur in "leetcode", so we return -1. Constraints: 1 <= haystack.length, needle.length <= 104 haystackandneedleconsist of only lowercas...
LeetCode28. Find the Index of the First Occurrence in a String CacheL1ne 来自专栏 · Leetcode刷题笔记 解题思路 二重循环,没什么特别的 class Solution { public: int strStr(string haystack, string needle) { int index = 0; bool flag = true; for(int i = 0; i < haystack.size(); i+...
链接:https://leetcode.cn/problems/find-the-index-of-the-first-occurrence-in-a-string 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 题意是给定一个 haystack 字符串和一个 needle 字符串,在 haystack 字符串中找出 needle 字符串出现的第一个位置 (从0开始)。如果不存在,则返回...