Can you solve this real interview question? Find Peak Element - A peak element is an element that is strictly greater than its neighbors. Given a 0-indexed integer array nums, find a peak element, and return its index. If the array contains multiple pea
https://leetcode.com/problems/find-peak-element/ 思路就是二分查找。如果mid在波峰的递减部分,那么e = mid - 1. 如果mid在波峰的递增部分,那么s = mid + 1. 如果mid在波峰,那么返回。 my code: 效率不高。 class Solution(object): def findPeakElement(self, nums): """ :type nums: List[int]...
classSolution {publicintfindPeakElement(int[] nums) {if(nums.length==0 || nums==null)return0;intL = 0;intR = nums.length - 1;while(L<R){intmid = (L+R+1)>>>1;if(nums[mid-1]>nums[mid]){ R= mid-1; }else{ L=mid; } }returnL; } }...
题目链接:https://leetcode.com/problems/find-peak-element/题目: A peak element is an element that is greater than its neighbors. num[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peak...
Given a sorted integer array arr, two integers k and x, return the k closest integers to x in the array. The result should also be sorted in ascending order. An integer a is closer to x than an integer b if: |a - x| < |b - x|, or |a - x| == |b - x| and a < b...
leetcode 162. 寻找峰值(Find Peak Element) 题目描述: 峰值元素是指其值大于左右相邻值的元素。 给定一个输入数组nums,其中nums[i] ≠ nums[i+1],找到峰值元素并返回其索引。 数组可能包含多个峰值,在这种情况下,返回任何一个峰值所在位置即可。 你可以假设nums[-1] = nums[n] = -∞。
Find First and Last Position of Element in Sorted Array leetcode34 Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm’s runtime complexity must be in the order of O......
A peak element is an element that is greater than its neighbors. Given an input array wherenum[i] ≠ num[i+1], find a peak element and return its index. The array may contain multiple peaks, in that case return the index to any one of the peaks is fine. ...
The array may contain mu...LeetCode: 162. Find Peak Element LeetCode: 162. Find Peak Element 又是一道加了锁,不能做的题。 只好做 162 咯。 题目描述 A peak element is an element that is greater than its neighbors. Given an input array nums, where nums[i] ≠ nums[i+1], find a ...
If the target is found, it continues searching in the right half (left = mid + 1), otherwise, it searches in the left half (right = mid - 1). The loop exits when left > right, and right will point to the last occurrence of the target or the last element smaller than the target...