所以这里提供一个不先排序的算法。 注意:题目要求是find the first missingpositive integer。 也就是说,即便你给的数组是4 5 6 7,看似都一一排好序,但是返回值一定是1,也就是如果给的数组是4 5 7 8 ,答案不是6,是1。 因此,有了这个性质,我们就能i和A[i]是否相等来做判断了。“实现中还需要注意一个...
所以题目是需要你在从1 ~ +∞的范围中,找到没有在输入数组出现过的最小的正publicclassSolution {publicintfirstMissingPositive(int[] nums) {intlen=nums.length;if(nums==null||len==0) return1;//首先判断当前元素是否为整数,否则直接过,并且num[j]<len不然造成数组越界,最后判断如果nums[j]-1!=[j]...
Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. For example, Given nums = [0, 1, 3] return 2. Note: Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra spa...
Your algorithm should run in O(n) time and uses constant extra space. Solution class Solution { public int firstMissingPositive(int[] A) { int i = 0; while(i < A.length){ //we want every A[i] = i+1, so we can find the first missing one //if A[i] is negative or out of...
class Solution { public: int firstMissingPositive(vector<int>& nums) { bucket_sort(nums); for(int i = 0; i < nums.size(); ++i) { if(nums[i] != i + 1) { return i + 1; } } return nums.size() + 1; } private: void bucket_sort(vector<int>& nums) { for(int i = 0...
题目链接: https://leetcode.com/problems/first-missing-positive/?tab=Description 给出一个未排序的数组,求出第一个丢失的正数。 给出组合为int []nums = {0,1,3,-1,2,5}; 下面为按照参考代码1执行交换运算的输出结果 0 1 3 -1 2 5
1 <= nums.length <= 5 * 105 -231<= nums[i] <= 231- 1 题目大意:找到第一个缺失的正整数 解题思路:先讲数组放到map中,然后依次对比map中是否存在i,如果不存在就返回结果 classSolution(object):deffirstMissingPositive(self,nums):""":type nums: List[int]:rtype: int"""ifnums[0]==1andnums...
Given an unsorted integer array, find the smallest missing positive integer. 给定一个未排序的整数数组,找出其中缺少的最小的正整数。 Example 1: Input: [1,2,0] Output: 3 Example 2: Input: [3,4,-1,1] Output: 2 Example 3: Input: [7,8,9,11,12] ...
[LeetCode] 41. First Missing Positive ☆☆☆(第一个丢失的正数),Givenanunsortedintegerarray,findthesmallestmissingpositiveinteger.Examp
LeetCode:First Missing Positive LeetCode 题目链接:First Missing Positive Given an unsorted integer array, find the first missing positive integer. For example, Given [1,2,0] return 3, and [3,4,-1,1] return 2. Your algorithm should run in O(n) time and uses constant space....