class Solution { public int firstMissingPositive(int[] nums) { int n = nums.length;<spanclass="hljs-comment">// 基本情况</span><spanclass="hljs-keyword">int</span>contains =<spanclass="hljs-number">0</span>;<spanclass="hljs-keyword">for</span>(<spanclass="hljs-keyword">int</...
Smallest Missing Non-negative Integer After Operations Maximum Number of Integers to Choose From a Range II 参考资料: https://leetcode.com/problems/first-missing-positive/ https://leetcode.com/problems/first-missing-positive/discuss/17071/My-short-c++-solution-O(1)-space-and-O(n)-time LeetCo...
class Solution { public: int firstMissingPositive(vector<int>& nums) { bucket_sort(nums); for(int i = 0; i < nums.size(); ++i) { if(nums[i] != i + 1) { return i + 1; } } return nums.size() + 1; } private: void bucket_sort(vector<int>& nums) { for(int i = 0...
要求常数,一般情况,要么是贪心,要么是用位运算记录信息,要么是用输入数组记录信息。 官方题解的原地哈希比较巧妙,将下标i的元素转为负数,用来表示数字i已经存在; 当然,将nums[i]和在下标nums[i]位置的元素持续交换的解法,也是可以的。
publicintfirstMissingPositive(int[]nums){intn=nums.length;//将正数移到前边,并且得到正数的个数intk=positiveNumber(nums);for(inti=0;i<k;i++){//得到要标记的下标intindex=Math.abs(nums[i])-1;if(index<k){//判断要标记的位置的数是不是小于 0,不是小于 0 就取相反数inttemp=Math.abs(nums...
[Leetcode][python]First Missing Positive/缺失的第一个正数,题目大意给定一个未经排序的数组,寻找第一个缺失的正整数你的算法应该满足O(n)时间和常数空间复杂度解题思路参考:http://bookshadow.com/weblog/2015/09/14/leetcode-first-missing-positive/尽可能地把数组
[Leetcode] First Missing Positive First Missing Positive Given an unsorted integer array, find the first missing positive integer. For example, Given [1,2,0] return 3, and [3,4,-1,1] return 2. Your algorithm should run in O(n) time and uses constant space....
参考:http://bookshadow.com/weblog/2015/09/14/leetcode-first-missing-positive/ 尽可能地把数组中不大于n(n为数组长度)的正整数放置到下标+1与其数值相同的位置上 第一个下标+1与数值不同的数字,即为所求。 例如数组nums = [3,4,-1,1],调整位置后的结果为:[1,-1,3,4] ...
public int missingNumber(int[] nums) { int res = 0; for(int i = 0; i <= nums.length; i++){ res ^= i == nums.length ? i : i ^ nums[i]; } return res; } } First Missing Positive Given an unsorted integer array, find the first missing positive integer. ...
fromtypingimportListclassSolution:deffirstMissingPositive(self,nums:List[int])->int:foriinrange(len(nums)):while0<nums[i]<=len(nums)andnums[nums[i]-1]!=nums[i]:nums[nums[i]-1],nums[i]=nums[i],nums[nums[i]-1]foriinrange(0,len(nums)):ifnums[i]!=(i+1):returni+1returnlen...