Smallest Missing Non-negative Integer After Operations Maximum Number of Integers to Choose From a Range II 参考资料: https://leetcode.com/problems/first-missing-positive/ https://leetcode.com/problems/first-missing-positive/discuss/17071/My-short-c++-solution-O(1)-space-and-O(n)-time LeetCode All in One 题目讲解汇总(...
第一个缺失的正整数 first-missing-positive 题目描述 给出一个无序的整数型数组,求不在给定数组里的最小的正整数 例如: 给出的数组为[1,2,0] 返回3, 给出的数组为[3,4,-1,1] 返回2. 你需要给出时间复杂度在O(n)之内并且空间复杂度为常数级的算法 Given an unsorted integer array, find the ...
First Missing Positive -- LeetCode 原题链接: http://oj.leetcode.com/problems/first-missing-positive/ 这道题要求用线性时间和常量空间,思想借鉴到了Counting sort中...[Leetcode] First Missing Positive First Missing Positive Given an unsorted integer array, find the first missing positive integer....
class Solution { public int firstMissingPositive(int[] nums) { int n = nums.length;<spanclass="hljs-comment">// 基本情况</span><spanclass="hljs-keyword">int</span>contains =<spanclass="hljs-number">0</span>;<spanclass="hljs-keyword">for</span>(<spanclass="hljs-keyword">int</...
-231<= nums[i] <= 231- 1 题目大意:找到第一个缺失的正整数 解题思路:先讲数组放到map中,然后依次对比map中是否存在i,如果不存在就返回结果 classSolution(object):deffirstMissingPositive(self,nums):""":type nums: List[int]:rtype: int"""ifnums[0]==1andnums[len(nums)-1]==len(nums)andsum...
[Leetcode] First Missing Positive First Missing Positive Given an unsorted integer array, find the first missing positive integer. For example, Given [1,2,0] return 3, and [3,4,-1,1] return 2. Your algorithm should run in O(n) time and uses constant space....
public int missingNumber(int[] nums) { int res = 0; for(int i = 0; i <= nums.length; i++){ res ^= i == nums.length ? i : i ^ nums[i]; } return res; } } First Missing Positive Given an unsorted integer array, find the first missing positive integer. ...
class Solution: # 本题直接用个for循环即可# 本题需要注意的是给定的未排序数组列表nums里面可能有重复数字,所以下面判断相邻两个数大小关系的的时候需要注意 def firstMissingPositive(self, nums): """ :type nums: List[int]-->给定的未排序数组列表:rtype: int-->final_min_number """ # 定义最终找到...
publicclassSolution{ publicintfirstMissingPositive(int[]nums){ if(nums==null||nums.length==0){ return1; } // 创建一个查找表,用来记录 1~nums.length 中数字出现的情况 boolean[]exist=newboolean[nums.length]; for(inti=0;i<nums.length;i++){ ...
LeetCode:First Missing Positive Given an unsorted integer array, find the first missing positive integer. For example, Given[1,2,0]return3, and[3,4,-1,1]return2. Your algorithm should run inO(n) time and uses constant space 寻找数组中缺失的最小正整数...