Question Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the minimum element. Answer 借用以下网上的翻译: 把一个数组最开始的若干个元素搬到数组的末尾,我们称之为数组的旋转。 ...
Find the minimum element. The array may contain duplicates. 思路: 1.题目中指出sorted array,find target使用二分法。 2.分为以下三种情况 (1)数组只有一个元素:nums[0]即为最小值。 (2)数组不是rotated sorted array,退化为sorted array:nums[0]即为最小值。 (3)数组是rotated sorted array:nums[star...
来自专栏 · LeetCode Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input...
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. The array may contain duplicates. Example 1: Input: [1,...
Description Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. The array m…
Find the minimum element. You may assume no duplicate exists in the array. Example 1: Input: [3,4,5,1,2] Output: 1 1. 2. Example 2: Input: [4,5,6,7,0,1,2] Output: 0 1. 2. 题解: 154包含重复,同样代码 classSolution{ ...
You are given an integer array nums, an integer array queries, and an integer x.For each queries[i], you need to find the index of the queries[i]th occurrence of x in the nums array. If there are fewer than queries[i] occurrences of x, the answer should
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这就是最基本的二分查找问题,对应于 LeetCode 35. 搜索插入位置:给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引。如果目标值不存在于数组中,返回它将会被按顺序插入的位置。我们已经分析过,target 按顺序插入的位置,就是满足 x≥ target 的第一个...
Find the minimum element. The array may contain duplicates. *//* MARK: - 题目翻译: 和Find Minimum in Rotated Sorted Array 题目类似 如果 数组中有重复元素怎么办 这会影响运行的时间复杂度吗 假设一个按升序排序的数组在你事先未知的某个旋转点旋转。