Find the length of the curve.r(t)=<2t,t^2, 13t^3>, 0≤ t≤ 1 相关知识点: 试题来源: 解析 73. r(t)=<2t,t^2, 13t^3> ⇒ \ r'(t)=<2,2t,t^2> ⇒|r'(t)|=√ (2^2+(2t)^2+(t^2)^2)=√ (4+4t^2+t^4)=√ ((2+t^2)^2)=2+t^2 for 0≤ t≤ 1....
Answer to: Find the length of the curve. y = x^2 - \frac{\ln(x)}{8} from x = 1 to x = e By signing up, you'll get thousands of step-by-step...
Answer to: Find the length of the curve y= \sqrt{4 - x^2} for 0 less than or equal to x less than or equal to 2. Note: the integral representing...
百度试题 结果1 题目Find the length of the curve defined by , , . 相关知识点: 试题来源: 解析 7T 反馈 收藏
Find the length of the curve x=−6cos(θ),y=−6sin(θ),0≤θ≤π. Arc Length: The arc length of a curve is calculated by integrating the arc length differential along the desired interval. The arc length differential for a parametric ...
百度试题 结果1 题目Find the length of the curve defined by x=cos t, y=sin t, 0≤q t≤q π . 相关知识点: 试题来源: 解析 π 反馈 收藏
Answer to: Find the length of the curve x = e^t cost (t), \ y = e^t sin (t),\ 0 \le t \le \pi By signing up, you'll get thousands of step-by-step...
Find the length of the curve. $$y = \left ( 1 - x^\frac{2}{3} \right )^{\frac{3}{2}}, \; \frac{\sqrt{2}}{4} \leq x \leq 1 $$ Integration and Differentiation Method: Various derivative and integration formulas and methods must be k...
Therefore, $$ L = \int _ { 0 } ^ { 1 } \sqrt { 1 + ( \frac { d y } { d x } ) ^ { 2 } } d x \\ = \int _ { 0 } ^ { 1 } \sqrt { 1 + ( 2 \sqrt { 2 } x ^ { 1 / 2 } ) ^ { 2 } } d \\ = \int _ { 0 } ^ { 1 } \sqrt { ...
The given function is: {eq}y = \dfrac{2x^2}{3} {/eq} We have to find the length of the curve from {eq}x = 0\ to\ x = \frac{5}{4} {/eq} The... Learn more about this topic: How to Find the Arc Length of a Function ...