Find the length of the curve.(t)=+t^2+t^3, 0≤ t≤ 1 相关知识点: 试题来源: 解析 1(27)(13^(32)-8) (t)=+t^2+t^3 ⇒ '(t)=2t+3t^2 ⇒ |'(t)|=√ (4t^2+9t^4)=t√ (4+9t^2) [since t≥q 0]. Then L=\int ^{1}_{0}|\mathrm{r}'(t)|\d t=\...
Find the length of the curve.r(t)=<2t,t^2, 13t^3>, 0≤ t≤ 1 相关知识点: 试题来源: 解析 73. r(t)=<2t,t^2, 13t^3> ⇒ \ r'(t)=<2,2t,t^2> ⇒|r'(t)|=√ (2^2+(2t)^2+(t^2)^2)=√ (4+4t^2+t^4)=√ ((2+t^2)^2)=2+t^2 for 0≤ t≤ 1....
百度试题 结果1 题目37. Find the length of the curve with the equat sinx^(2/3)+y^(2/3)=1^a060.40.2-1-0.5C0.5-D2-0.40.6a) 6b) 4c) 24d) 12e) None of the above 相关知识点: 试题来源: 解析 a 反馈 收藏
Find the length of the curve. $$y = \left ( 1 - x^\frac{2}{3} \right )^{\frac{3}{2}}, \; \frac{\sqrt{2}}{4} \leq x \leq 1 $$ Integration and Differentiation Method: Various derivative and integration formulas and methods must be k...
Find the length of the curve. The curve r = 2 sin^3 (theta/3), 0 less than or equal to theta less than or equal to pi/2. Find the length of the curve. The curve r = 2sin^3(theta/3), 0 less than or equal to theta less than or ...
Answer to: Find the length of the curve x= \frac{y^3}{6} + \frac{1}{2y} from y=2 \enspace to \enspace y =3 By signing up, you'll get thousands...
Find the length of the curve {eq}x = 4 \cos \theta + \theta \sin \theta, y = 4 \sin \theta - \theta \cos \theta; \quad 0 \leq \theta \leq \pi {/eq} Arc Length: To compute the exact length of a curve on an interval, ...
Question: Find the length of the curve. x=31(t3−3t),y=t2+4,0≤t≤1 A) 31 B) 32 C) 2 like if right and fats Show transcribed image text There are 2 steps to solve this one. Solution Share Step 1 Given curve are - x=13(t3−3t)View t...
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x^2+y^2=4 and the plane x+y+z=2.相关知识点: 试题来源: 解析 13.5191 Let C be the curve of intersection. The projection of C onto the xy-plane is the ellipse 4x^2+y^2=4 or x^2+(...
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