In this tutorial, we will learn how to find the factorial of a given number using Python program?
Here, we are going to implement logic to find factorial of given number in Python, there are two methods that we are going to use 1) using loop and 2) using recursion method.
#!/use/bin/env python # _*_ coding:utf-8 _*_ # 只需脚本是让用户输入一个数字,并把值赋值给变量n n = int(input("Pless Numbers: ")) # 如果n大于10 if n > 10: # 输出n > 10 print("n > 10") # 如果n等于10 elif n == 10: # 输出n == 10 print("n == 10") # 否则 ...
I have a Python question imagine variable x below. I want to write a regular expression that helps me finds any repeating single digits. Like 1 is not repeated, but 2 is mentioned twice, and 3 is 3 times. this is what I thought, but this just gives me
Python Code: # Define a function 'absent_digits' that finds the absent digits from the given list 'n'.defabsent_digits(n):# Create a set containing all possible digits (0 to 9).all_nums=set([0,1,2,3,4,5,6,7,8,9])# Convert the list 'n' to a set of integers.n=set([int...
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+ 1 145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145. Find the sum of all numbers which are equal to the sum of the factorial of their digits. Note: as 1! = 1 and 2! = 2 are not sums they are not included. ...
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