python代码如下:#输入正整数NN=int(input())#将整数N转换为字符串,然后将每个数字作为字符串列表的元素digits=list(str(N))#计算位数(字符串的长度)和各位数字之和num_digits=len(digits)sum_of_digits=sum(int(digit)fordigitindigits)#输出结果print(num_digits,sum_of_digits)这段代码首先接受一个正整数N...
python题目 Write a function that computes and returns the sum of the digits in an integer. Use the following function header: def sum_digits(number): For example sum_digits(234) returns 9. Use the % operator to extract the digits and the // operator to remove the extracted digit. For...
Instructions In this kata, you must create a digital root function. A digital root is the recursive sum of all the digits in a number. Given n, take t
Write a Python program to calculate sum of digits of a number. Pictorial Presentation: Sample Solution: Python Code: # Prompt the user to input a four-digit number and convert it to an integer.num=int(input("Input a four-digit number: "))# Extract the thousands digit (x).x=num//1000...
python题目Write a function that computes and returns the sum of the digits in an integer. Use the following function header:def sum_digits(number):For example sum_digits(234) returns 9. Use the % operator to extract the digits and the // operator t
Python基础 变量和数据类型 变量 首先我们要理解如何保存数据,以及把数据保存成哪种格式。 需要把图像变量设置为保存数据的容器,变量命名规则: 1. 变量名必须以字母或下划线开头; 2. 变量名的剩余部分可以由字母、数字和下划线组成; 3. 绝对不能使用Python内置的关键字。
Sum of Digits time limit per test 2 seconds memory limit per test 265 megabytes input standard input output standard output Having watched the last Harry Potter film, little Gerald also decided to practice magic. He found in his father’s magical book a spell that turns any number in the ...
题目链接:Given Length and Sum of Digits 题目描述 You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the dec...
Write a Python program to calculate the sum of all digits of the base to the specified power. Sample Solution: Python Code: defpower_base_sum(base,power):returnsum([int(i)foriinstr(pow(base,power))])print(power_base_sum(2,100))print(power_base_sum(8,10)) ...
Input: n = 4421Output: 21Explanation: Product of digits = 4 * 4 * 2 * 1 = 32Sum of digits = 4 + 4 + 2 + 1 = 11 Result = 32 - 11 = 21 Constraints: 1 <= n <= 10^5 这道题给了一个正整数n,让求其每一位的数字的乘积减去每一位数字的和,并不算一道难题,只要知道如何取出每...