Given"abcabcbb", the answer is"abc", which the length is 3. Given"bbbbb", the answer is"b", with the length of 1. Given"pwwkew", the answer is"wke", with the length of 3. Note that the answer must be a substring,"pwke"is asubsequenceand not a substring. 题目解析:意思就是...
Given"pwwkew", the answeris"wke",withthe lengthof3.Notethat the answer must be a substring,"pwke"isa subsequenceandnota substring. 思路: 遍历字符串,每个字符串都在map中查找是否有相同的字符,如果存在相同元素s[j],则计算(i-j)来计算长度;新的index_0即为j+1;然后在map中删除该元素,以确认下...
formed using a, b and c under given constraints minimum number of flips count occurrences of anagrams rearrange a string print bracket number longest palindromic subsequence preorder to postorder of bst maximum difference of zeros and ones in binary string sum of all substrings of a number najpf...
0387-First-Unique-Character-in-a-String 0388-Longest-Absolute-File-Path 0389-Find-the-Difference 0390-Elimination-Game 0391-Perfect-Rectangle 0392-Is-Subsequence 0393-UTF-8-Validation 0394-Decode-String 0398-Random-Pick-Index 0404-Sum-of-Left-Leaves 0412-Fizz-Buzz 0414-Third-...
0344-reverse-string.py 0347-top-k-frequent-elements.py 0355-design-twitter.py 0367-valid-perfect-square.py 0371-sum-of-two-integers.py 0374-guess-number-higher-or-lower.py 0377-combination-sum-iv.py 0392-is-subsequence.py 0394-decode-string.py 0410-split-array-larges...
https://leetcode.com/problems/find-duplicate-file-in-system/ 题目描述 Given a list of directory info including directory path, and all the files with contents in this directory, you need to find out all the groups of duplicate files in the file system in terms of their path...
(_ file: String.SubSequence, _ dir: String.SubSequence) ->(String, String) {16let startIndex = file.index(of:"(")!17let endIndex =file.index(before: file.endIndex)18let contents = String(file[file.index(after: startIndex)..<endIndex])19let path = String(file[file.startIndex..<...
链接:https://leetcode-cn.com/problems/find-the-most-competitive-subsequence 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。 思路是单调栈。题意是寻找一个长度为 K 的子序列且需要确保竞争力尽可能大,但是我第一次做的时候只是一味地照顾到了竞争力(栈中元素单调增)而没有照顾到栈中...
Find longest word in dictionary that is a subsequence of a given string 贪心算法: 1)将D按字符串的长度,从长到短排序。 2)从D[0]开始,尝试找到这个字符串(这里叫word)是S的子序列。 3)从word[0]开始,遍历S,尝试在S中找到这个字符;一旦找到,接着从当前位置的后面找word[1]是否在S中,以此类推。
Given"pwwkew", the answer is"wke", with the length of 3. Note that the answer must be a substring,"pwke"is asubsequenceand not a substring. 翻译 给定一个字符串,找到最长的子串的长度,这个子串不存在重复的字符。 例如: 输入”abcabcbb”, 符合条件的子串就是”abc”, 长度为3。