Leetcode: 1755. Closest Subsequence Sum Description You are given anintegerarraynumsandanintegergoal. You wanttochoose a subsequenceofnums such that the sumofits elementsisthe closest possibletogoal. Thatis,ifthe sumofthe subsequence'selementsissum,thenyou wanttominimize the absolute differenceabs(su...
3 def sums(arr): 5 sumset = {0} 6 for a in arr: 7 sumset |= set(a+x for x in sumset) 8 return sumset 9 return min(abs(seq-goal) for seq in sums(nums)) 更优解 那我们现在来想一下,给定时间复杂度是O(2^N),有什么方式可以大幅降低时间复杂度呢? 如果能把原数列一分为二,分...
map<int, int> m; int sum[1000005]; int sum2[1000005]; int p; void fun(int n, int i, int s,vector<int>& nums, int* sum) { if (m[s] == 0) { m[s] = 1; sum[p++] = s; } for (int j = i + 1; j < n; j++) { fun(n, j, s+nums[j], nums, sum); } }...
Closest Subsequence Sum 题解:数组的长度为40,找出全部子集一共有240种可能性,如果把一个数组平均分成两部分,分别算出两部分的所有子集和,每部分有220种可能, 然后再二分查找答案... 49400 Closest Divisors i result[1] = y2 // i return result Reference https://leetcode.com/problems/closest-divisors ...
ans = min(ans, abs(sum[i] - goal)); } p =0;for(inti=n; i < nums.size(); i++) { fun(nums.size(), i, nums[i],nums, sum2); }for(inti=0; i < p; i++) { ans = min(ans, abs(sum2[i] - goal)); } sort(sum, sum + p1);// 1 2 5 6for(inti=0; i < p...
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2). https://leetcode.com/problems/3sum-closest/#/solutions http://www.cnblogs.com/EdwardLiu/p/4012459.html 先将数组排个序,然后开始遍历数组,思路跟那道三数之和很相似,都是先确定一个数,然后用两个指针left和right来滑动寻找另...