Given an array of integers, the task is to find the maximum subarray sum possible of all the non-empty arrays. Input: [−2, 1, −3, 4, −1, 2, 1, −5, 4] Output: 6 Explanation: Subarray [4, −1, 2, 1] is the max sum contiguous subarray with a sum of 6. We ...
1publicclassSubarrayWithGivenSum {2publicstaticint[] findSubarrayWithGivenSum(int[] arr,intsum) {3int[] range =newint[2];4range[0] = -1; range[1] = -1;5if(arr ==null|| arr.length == 0 || sum < 0) {6returnrange;7}8intstart = 0;9intcurrSum = arr[0];10for(intend = ...
classSolution{publicbooleanfindSubarrays(int[]nums){HashMap<Integer,Integer>map=newHashMap<>();int n=nums.length;for(int i=0;i<n-1;i++){int sum=nums[i]+nums[i+1];if(map.containsKey(sum)){map.put(sum,map.get(sum)+1);}else{map.put(sum,1);}}for(Integer k:map.keySet()){i...
We need to find maximum sum subarray in a given range.Let’s say we have 'a' as a parent node and p and q as its child nodes. Now we need to build data for a from p and q such that node a can give the maximum sum subinterval for its range when queried....
maxWrap : maxKadaneSum; } // Function to find the maximum sum of subarray using Kadane's algorithm int kadane(int arr1[], int n) { int maxUpto = 0, maxAtPos = 0; int i; for (i = 0; i < n; i++) { maxAtPos = maxAtPos + arr1[i]; if (maxAtPos < 0) maxAtPos ...
In computer science, the maximum sum subarray problem is the task of finding a contiguous subarray with the largest sum, within a given one-dimensional array A[1...n] of numbers. Formally, the task is to find indices and with, such that the sum is as large as possible. ...
Find all maximum sub-array in which all pairs have their sum >= k. I feel it can be solved using monotonic queue likethis solution, but i am not able to think correct answer. Please give some hints. e.g. Array :[ 1 5 2 3 6 5 4 2 2 8 ] and K = 8 ...
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Kadane's algorithm. Kadane's algorithm is an efficient way to find the maximum subarray sum in ...
Given an array of positive and negative integers find the first subarray with zero sum? no 0's will be a part of the input array and handle all the edge cases A: 1. iterate through the array once, and take the sum from 0 to every other index of the array. ...