Find the points on the given curve where the tangent line is horizontal or vertical. r=e^(θ ) 相关知识点: 试题来源: 解析 horizontal tangents at (e^(π (n- 1/4)),π (n- 14)).vertical tangents at (e^(π (n+ 1/4)),π (n+ 14)). r=e^(θ ) ⇒ x=rcos θ=e^(θ...
Set the derivative equal to ( 0) then solve the equation( -e^(-x)x+e^(-x)=0). ( x=1) Solve the original function( f(x)=xe^(-x)) at ( x=1). ( 1/e) The horizontaltangentlines on function( f(x)=xe^(-x)) are ( y=1/e). ( y=1/e)反馈...
Find all points on the curve where the tangent line is horizontal y = (\frac{x^6}{6}) - (\frac{x^2}{2}) + 1. Find the points on the curve y = 2x^{3} + 3x^{2} - 12x + 5 where the tangent line is hor...
Find the points on the interval[0,2π)where the graph of the functionf(x)=2sin(x)+sin2(x)has a horizontal tangent line. Tangent lines: The derivative of a function tells us the slope of that function at every point. Ano...
Find the point(x,y), at which the graph ofy=8x2+6x−7has a horizontal tangent. Question: Tangent and Equation: The tangent at the point of contact of the tangent and the curve can be horizontal or vertical if the tangent is horizontal, the slope is zero, else the...
Find the points on the given curve where the tangent line is horizontal or vertical. r=e^(θ ) 相关知识点: 试题来源: 解析 horizontal tangents at (e^(π (n- 1/4)),π (n- 14)). vertical tangents at (e^(π (n+ 1/4)),π (n+ 14))....
Find all points on the graph of the function f(x) = 2 \sin x + sin^2 x at which the tangent line is horizontal. (Use n as your arbitrary integer.} (x, y) = ( ) (smaller y-value) (x, y) = ( ) (larg Find the points where are horizontal tangents for ...
consider the curve given by y的平方 =2+xy(1) show that dy/dx = y/(2y-x)(2) find all points (x,y) on the curve where the line tagent to the curve has slope 1/2(3)show that there are no points (x,y) on the curve where the line tangent to the curve is horizont...
Because the tangent line will be horizontal at a maximum or minimum point of a curved function, it will have a slope of zero. This fact is sometimes used to find maxima and minima of functions, because their first derivative will be zero at those points. ...
Find the value on the horizontal axis or x value of the point of the curve you want to calculate the tangent for and replace x on the derivative function by that value. To calculate the tangent of the example function at the point where x = 2, the resulting value would be f'(2) =...