Find the Horizontal Tangent Line y=cos(x) ( y=(cos)(x)) 相关知识点: 试题来源: 解析 Set( y) as a function of ( x). ( f(x)=(cos)(x)) The derivative of ( (cos)(x)) with respect to ( x) is ( -(sin)(x)). ( -(sin)(x)) Set the derivative equal to ( 0) th...
( f(x)=2x) Find the derivative. ( 2) Since ( 2≠ 0), there are no solutions. No solution There are no solution found by setting the derivative equal to ( 0), ( 2=0) so there are no horizontaltangentlines. No horizontaltangentlines found反馈...
Function:r=4+4sin(θ)⇒f(θ)=4+4sin(θ) Sketch: (b) Horizontal tangent line... Learn more about this topic: Graphing Polar Equations & Coordinates | Process & Examples from Chapter 24/ Lesson 1 15K Learn how to graph polar equations and plot polar coordinates. S...
How to find all points on the curve x = t^2 - t ; y = 2 squareroot(t) where the tangent line is vertical ? Find all points on the curve y^2 + xy = x + 3y - 6 where the tangent lines are horizontal and vertical.
Find the value on the horizontal axis or x value of the point of the curve you want to calculate the tangent for and replace x on the derivative function by that value. To calculate the tangent of the example function at the point where x = 2, the resulting value would be f'(2) =...
Since ( =0), the equation will always be true. Always true The horizontaltangentlines on function( f(x)=((4-x^(2/3)))^(3/2),-((4-x^(2/3)))^(3/2)) are ( y=Always(true)). ( y=Always) true反馈 收藏
Find the points on the given curve where the tangent line is horizontal or vertical. r=e^(θ ) 相关知识点: 试题来源: 解析 horizontal tangents at (e^(π (n- 1/4)),π (n- 14)).vertical tangents at (e^(π (n+ 1/4)),π (n+ 14)). r=e^(θ ) ⇒ x=rcos θ=e^(θ...
= 0 and so y = f(x) has a horizontal tangent line at ( 1 3 , f( 1 3 )); and as f(x) is (right) continuous at 0, and lim x→0 + |f (x)| = ∞, y = f(x) has a vertical tangent line at (0, 0). Example 2 Find all the points on the graph y = x √ 1 ...
Solve for the function with the value for x you just inserted. The example function is 12(9) + 2 = 110. This is the slope of the tangent line to the original function at that x value. TL;DR (Too Long; Didn't Read) Because the tangent line will be horizontal at a maximum or mi...
Find an equation of the line tangent to the curve x = t + \cos t, y = 2 - \sin t at the point where t = \frac{\pi}{6} Find all values of t in (0, \pi), for which the tangent line to the graph of x(t) = t + \cos 2t, y(t) = t - cos 2t, is horizonta...