public int findMin(int[] nums) { int start = 0; int end = nums.length - 1; while (start < end) { int mid = (start + end) >>> 1; if (nums[mid] > nums[end]) { start = mid + 1; } else { end = mid; } } return nums[start]; } 解法二 解法一中我们把 mid 和end ...
1. 无重复 Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e.,0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路:这个是找最小,和找指定数字其实差不多的。画个示意图吧 二分...
[0,1,2,4,5,6,7]if it was rotated7times. Notice that rotating an array[a[0], a[1], a[2], ..., a[n-1]]1 time results in the array[a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated arraynumsof unique elements, returnthe minimum element of...
153. Find Minimum in Rotated Sorted Array 题目 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e.,[0,1,2,4,5,6,7]might become[4,5,6,7,0,1,2]). Find the min element. You may assume no duplicate exists in the array. Example ...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. 0 1 2 4 5 6 7might become4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 思路: 有序数组旋转后,如果mid元素比low大,则左边有序,右边乱序,考虑最左元素是否最小元素...
Can you solve this real interview question? Find Minimum in Rotated Sorted Array - Suppose an array of length n sorted in ascending order is rotated between 1 and n times. For example, the array nums = [0,1,2,4,5,6,7] might become: * [4,5,6,7,0,1,2] if
Notice that rotating an array [a[0], a[1], a[2], ..., a[n-1]] 1 time results in the array [a[n-1], a[0], a[1], a[2], ..., a[n-2]]. Given the sorted rotated array nums of unique elements, return the minimum element of this array. ...
153 Find Minimum in Rotated Sorted Array "Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,1,2,4,5,6,7] might become [4,5,6,7,0,1,2]). Find the minimum element. ...
public class MinimumElementSortedAndRotatedArrayMain { public static void main(String[] args) { int arr[]={16,19,21,25,3,5,8,10}; System.out.println("Minimum element in the array : "+findMinimumElementRotatedSortedArray(arr,0,arr.length-1,5)); } public static int findMinimumElementRot...
Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. You may assume no duplicate exists in the array. 二分迭代法 复杂度 ...