[2,3], the median is(2 + 3) / 2 = 2.5 Design a data structure that supports the following two operations: void addNum(int num) - Add a integer number from the data stream to the data structure. double findMedian() - Return the median of all elements so far. For example: add(1...
[2,3], the median is (2 + 3) / 2 = 2.5 Design a data structure that supports the following two operations: void addNum(int num) - Add a integer number from the data stream to the data structure. double findMedian() - Return the median of all elements so far. For example: addN...
[2,3,4], the median is3 [2,3], the median is(2 + 3) / 2 = 2.5 Design a data structure that supports the following two operations: void addNum(int num) - Add a integer number from the data stream to the data structure. double findMedian() - Return the median of all elements...
} double findMedian() { if(n&1) { if(len1<len2) return *m2.begin(); else return *prev(m1.end()); } else return 1.0*(*prev(m1.end())+*m2.begin())/2; } }; /** * Your MedianFinder object will be instantiated and called as such: * MedianFinder* obj = new MedianFinder...
LeetCode 295. Find Median from Data Stream(multiset,heap) size效率 题解:要确保输入数字的操作和输出中位数的操作,都是低于等于Log(n)的效率。 那么怎么做呢?我们维护两个multiset ,内部是一棵红黑树。一个树A 维护的是较大值,树B维护的是较小值。A,B平分秋色。 中位数显然就是A里的最小值和B里的...
MedianFinder():来初始化MedianFinder这个对象; void addNum(int num):来从数据流中加入一个整数到我们的数据结构中; double findMedian():返回我们迄今为止加入的所有数的中位数; 这道题目有许多思路: 通过简单排序,利用数学公式解 通过插入排序,利用数学公式解 ...
https://leetcode.com/problems/find-median-from-data-stream/description/ 解题方法: 使用因为这个数据结构只需要找中位数,不需要pop,所以我们可以使用一个maxheap和一个minheap来储存数据。按照从小到大,maxheap存左半部分数据,minheap存右半部分数据。
void addNum(int num) - Add a integer number from the data stream to the data structure. double findMedian() - Return the median of all elements so far. For example: add(1)add(2)findMedian()->1.5add(3)findMedian()->2 分析
classMedianFinder{public:/** initialize your data structure here. */multiset<int>m1;multiset<int>m2;int n=0;int len1;int len2;MedianFinder(){m1.clear();m2.clear();len1=0;len2=0;}voidaddNum(int num){if(len1==0&&len2==0){m1.insert(num);len1++;n++;return;}multiset<int>::...
* MedianFinder obj = new MedianFinder(); * obj.addNum(num); * double param_2 = obj.findMedian(); */ 看了下讨论区,可以直接用优先队列来做,代码如下: classMedianFinder{public:/** initialize your data structure here. */MedianFinder(){}voidaddNum(intnum){small.push(num);//注意这里每个...