let p(x) =8x^(4)+4x^(3)-16x^(2)+10x+m Since , 2x-1 is a factor of p (x) then put p((1)/(2))=0 therefore 8((1)/(2))^(4)+4((1)/(2))^(3)-16((1)/(2))^(2)+10((1)/(2))+m=0 implies 8xx(1)/(16)+4xx(1)/(8) -16xx(1)/(4) +10((1)/(2)...
【解析】By the Factor theorem, as -2 is a factor then P(2)=0.(2)3+k(2)2-3(2)+6=08+4k=0 and so k=-2Nouvx^3+2x^2-3x+6=(x-2)(x^2+ax for some con-3)stant a.Equating coefficients of x2 gives: -2=-2+a i.e.,a=0Equating coefficients of a gives: -3=-2a-3 ...
Answer to: Given that x - 2 is a factor of x^3 - 4x^2 - 2x + k, find k. By signing up, you'll get thousands of step-by-step solutions to your...
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Find the value of k so that the graph of y=(x+5)2+k passes through the point (−12,−5). k=?Follow • 1 Add comment 1 Expert Answer Best Newest Oldest Patrick F. answered • 05/30/22 Tutor 5 (14) Patient and Inspiring Math Tutor See tutor...
结果1 题目 ID l Find the value(s) of m so that the simultaneous equations\(x^2+y^2=20x+y=m.,have two identical sets of real solutions. Find the solution set(s) to the simultaneous equations. 相关知识点: 试题来源: 解析 优质解答 反馈 收藏 ...
Answer to: Find the value of k so that lim_{x \rightarrow -2} G(x) = G(-2) A. k = 2 B. k = -2 C. k = -4 D. The value of k cannot be determined. By...
Point masses of mass m1, m2 and m3 are placed at the points (-1,0), (3,0) and (0,4). Suppose that mass m1 = 6 and mass m2 = 4. Find the value of m3 so that the y component of the center of mass ...
The given function is: $$f(x)=3x^2-4x $$ Replace {eq}x {/eq} by {eq}(x-k) {/eq} on both sides: $$\begin{align} f(x-k) &= 3(x-k)^2 -4(x-k) ... Learn more about this topic: Quadratic Function | Formula, Equations & Examples ...