Substituting value of a = – 3 in (i) we get 2×(– 3) + b = – 7 Or, – 6 + b = – 7 Or, b = – 1. Therefore, a = – 3, b = – 1 Q.(x - 2) is a factor of the expressionx3+ax2+bx+6. when this expression is divided by (x - 3) , it leaves the r...
百度试题 结果1 题目If x + 2 is a factor of , what is the value of b?相关知识点: 试题来源: 解析 7 7 反馈 收藏
解析 Yes, x − 2 is a factor.WORK SHOWN: P(2) = 2-1 − 3(23) + 5(2) − 2 = 16 − 24 + 10 − 2 = 0Yes, x − 2 is a factor.WORK SHOWN: P(2) = 2-1 − 3(23) + 5(2) − 2 = 16 − 24 + 10 − 2 = 0 ...
Let P(x)=x^3+kx^2-3x+6By the Factor theorem, as x-2 is a factor then P(2)=0∴(2)^3+k(2)^2-3(2)+6=0∴8+4k=0 and so k=-2Now x^3+2x^2-3x+6=(x-2)(x^2+ax-3) for some constant a.Equating coefficients of x^2 gives: -2=-2+a i.e., a=0Equating coef...
【题目】1Find the value ofk such that x-2 is a factor ofkx3-21x2+24x-4.求k的值使得-2为kx3-21x2+24x-4的因式.2Figure shows the graph ofy=15x2-63x+72.Q isa variable point on the graph in the first quadrant.P and R are the feet of the perpendiculars from Q to the x-axis...
解析 WORK SHOWN: f(2) = 10(2) − 15(2) − 16(2) + 12 = 80 − 60 − 32 + 12 = 0, so x − 2 is a factor. WORK SHOWN: f(2) = 10(2) − 15(2) − 16(2) + 12 = 80 − 60 − 32 + 12 = 0, so x − 2 is a factor....
百度试题 结果1 题目find the value of k such that x-2 is a factor of kx³-21x²+24x-4 相关知识点: 试题来源: 解析 x-2=0时,kx³-21x²+24x-4=0。因此将x = 2代入,得8k - 21×4 + 24×2 - 4 = 0。k = 5 反馈 收藏 ...
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For a polynomial p(x), the value of p(3) is -2. Which of the following must be true about p(x)? () A. x-5 is a factor of p(x). B. x-2 is a factor of p(x). C. x+2 is a factor of p(x). D. The remainder when p(x) is divided by x-3 is -2. 相关...
2.Set the value ofx: Sincex−2is a factor, we will substitutex=2into the polynomial. 3.Substitutex=2intoP(x): P(2)=2(25)−6(24)−2a(23)+6a(22)+4a(2)+8 4.Calculate powers of 2: 25=32,24=16,23=8,22=4 5.Substitute these values into the polynomial: ...