let p(x) =8x^(4)+4x^(3)-16x^(2)+10x+m Since , 2x-1 is a factor of p (x) then put p((1)/(2))=0 therefore 8((1)/(2))^(4)+4((1)/(2))^(3)-16((1)/(2))^(2)+10((1)/(2))+m=0 implies 8xx(1)/(16)+4xx(1)/(8) -16xx(1)/(4) +10((1)/(2)...
Answer to: Given that x - 2 is a factor of x^3 - 4x^2 - 2x + k, find k. By signing up, you'll get thousands of step-by-step solutions to your...
【解析】By the Factor theorem, as -2 is a factor then P(2)=0.(2)3+k(2)2-3(2)+6=08+4k=0 and so k=-2Nouvx^3+2x^2-3x+6=(x-2)(x^2+ax for some con-3)stant a.Equating coefficients of x2 gives: -2=-2+a i.e.,a=0Equating coefficients of a gives: -3=-2a-3 ...
The answer is no.It is a fine keyword and the calculated KGR is really great. Butit does not fulfill the criterium of search volume less than 250.However, part of the magic of the KGR is the ability to rank in Google quickly. I believe one of the factors is the search volume so ...
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Answer to: Find the value of k so that lim_{x \rightarrow -2} G(x) = G(-2) A. k = 2 B. k = -2 C. k = -4 D. The value of k cannot be determined. By...
Answer to: Find the values of k so that the function f(x) = \left\{\begin{matrix} 2k^2x + 1 & x \gt 1 \\ k- 2 & x \lt 1 \end{matrix}\right. ...
Find the value of k so that the graph of y=(x+5)2+k passes through the point (−12,−5). k=?Follow • 1 Add comment 1 Expert Answer Best Newest Oldest Patrick F. answered • 05/30/22 Tutor 5 (14) Patient and Inspiring Math Tutor See tutor...
The given function is: $$f(x)=3x^2-4x $$ Replace {eq}x {/eq} by {eq}(x-k) {/eq} on both sides: $$\begin{align} f(x-k) &= 3(x-k)^2 -4(x-k) ... Learn more about this topic: Quadratic Function | Formula, Equations & Examples ...