functionisBigEnough(element){returnelement>=15;}[12,5,8,130,44].findIndex(isBigEnough);// index of 4th element in the Array is returned,// so this will result in '3' 另请参见find()方法,它返回数组中找到的元素的值,而不是其索引。
_forEach(function(element) { console.log(element); }); //a //b //c 测试2: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 function logArrayElements(element, index, array) { console.log("a[" + index + "] = " + element); } 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ...
The index of first peak element in the array is: 3 The task is to write a C program that finds the index of the first peak element in a given array. A peak element is defined as an element that is greater than its neighbors. The program should traverse the array, identify the first...
Array.prototype._findIndex=function(fn/*,thisArg*/){if(this===null)thrownewTypeError('this is null or not defined');if(typeoffn !=='function')thrownewTypeError('fn must be a function');letthat =Object(this),len =this.length>>>0,thisArg =arguments[1];for(leti =0;i < len;i++)...
functionisBigEnough(element) { returnelement >= 15; } [12, 5, 8, 130, 44].find(isBigEnough);// 130 另请参见findIndex()方法,它返回数组中找到的元素的索引,而不是其值。 如果你需要找到一个元素的位置或者一个元素是否存在于数组中,使用Array.prototype.indexOf()或Array.prototype.includes()。
Example: Largest Element in an array #include <stdio.h> int main() { int n; double arr[100]; printf("Enter the number of elements (1 to 100): "); scanf("%d", &n); for (int i = 0; i < n; ++i) { printf("Enter number%d: ", i + 1); scanf("%lf", &arr[i]); }...
I have an array of non-repeating elements, X. I need to find the index of a specific element, 1.5 in X. I am trying to do index=find(X==1.5). However it just does not work. I gives me a "empty matrix". Does this have to do with the elements in the array being deci...
You are given an integer array nums, an integer array queries, and an integer x.For each queries[i], you need to find the index of the queries[i]th occurrence of x in the nums array. If there are fewer than queries[i] occurrences of x, the answer should
findIndex(function(a) {return a > 9;}) // 2LicenseThe MIT License (MIT)Copyright (c) 2013 Paul Miller http://paulmillr.comPermission is hereby granted, free of charge, to any person obtaining a copy of this software and associated documentation files (the “Software”), to deal in ...
Searches for an element that matches the conditions defined by a specified predicate, and returns the zero-based index of the first occurrence within an Array or a portion of it.