This post has shown, using three examples, how tofind the index of all matching elements in a list in Python. Your use case will determine which of the solutions to adopt. I do hope you found this tutorial help
Write a NumPy program to find the indices of elements equal to zero in a NumPy array. Sample Solution: Python Code: # Importing the NumPy library and aliasing it as 'np'importnumpyasnp# Creating a NumPy array 'nums' containing integersnums=np.array([1,0,2,0,3,0,4,5,6,7,8])# P...
输入:nums = [1,2,3,5,5,7] target = 5 输出:[3,4] 输入:nums = [1,5,8,9] target = 7 输出:[-1,-1] 解决思路:二分查找直到找到第一个目标值,再对目标值左右进行二分查找 Python代码: classSolution(object):defsearchRange(self, nums, target):""":type nums: List[int] :type target...
Can you solve this real interview question? Find First and Last Position of Element in Sorted Array - Given an array of integers nums sorted in non-decreasing order, find the starting and ending position of a given target value. If target is not found i
1. Find the Most Frequent Element using ‘collections.Counter()‘ Python’scollectionsmodule provides a convenient data structure calledCounterfor counting hashable objects in a sequence efficiently. When initializing aCounterobject, you can pass an iterable (such as a list, tuple, or string) or ...
Python Array Exercises, Practice and Solution: Write a Python program to find the first duplicate element in a given array of integers. Return -1 if there are no such elements.
解法 小结 题目链接 Find First and Last Position of Element in Sorted Array - LeetCode 注意点 nums可能为空 时间复杂度为O(logn) 解法 解法一:最普通的二分搜索,先找到一个target,然后向两边拓展。 classSolution{public:intbinarySearch(vector<int>& nums,inttarget){intleft =0,right = nums.size()-...
链接:https://leetcode-cn.com/problems/find-first-and-last-position-of-element-in-sorted-array python class Solution: def searchRange(self, nums: [int], target: int) -> [int]: # 二分法,时间O(logn), 空间O(1) def search(nums: [int], target: int) -> int: ...
Example 1: Using findIndex() method // function that returns even numberfunctionisEven(element){returnelement %2==0; }// defining an array of integersletnumbers = [1,45,8,98,7]; // returns the index of the first even number in the arrayletfirstEven = numbers.findIndex(isEven); ...
Given an array of integersnumssorted in ascending order, find the starting and ending position of a giventargetvalue. Iftargetis not found in the array, return[-1, -1]. You must write an algorithm withO(log n)runtime complexity.