时间复杂度:O(n),空间复杂度:O(n) funcfindDuplicates(nums []int)[]int{len:=len(nums);iflen<=1{returnnil} hashMap :=make(map[int]int) result := []int{}for_, v :=rangenums { _, exist := hashMap[v];if(exist) { result =append(result, v) }else{ hashMap[v] = v } }ret...
public: vector<int> findDuplicates(vector<int>& nums){ vector<int> res; for(inti = 0; i < nums.size(); i++){ intidx =abs(nums[i])-1; if(nums[idx] < 0) res.push_back(idx+1); nums[idx] = -nums[idx]; } returnres; } }; classSolution2{ public: vector<int> findDuplica...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the e...[leetcode] 442. Find All Duplicates in an Array 样例: Input: Output: 在数组中找出所有重复出现的数,要求时...
classSolution {publicList<Integer> findDuplicates(int[] nums) {//initializationList<Integer> result =newArrayList<Integer>();//for loop: get the new index, add to result if negative, change to negativefor(inti = 0; i < nums.length; i++) {//get the new indexintindex = Math.abs(nums...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
[leetcode]442. Find All Duplicates in an Array [leetcode]442. Find All Duplicates in an Array Analysis 周五ummmmmm—— [啊啊啊啊 paper结果要出来了,心塞] Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and......
442. Find All Duplicates in an Array 题目描述: Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appeartwiceand others appearonce. Find all the elements that appeartwicein this array. Could you do it without extra space and in O(n) runtime?
I need to load an array with random integers, however, the numbers need to be unique. The size of the array can vary based on user input, so using a static "if array[0] == array[1]", etc., is not going to work. I'm assuming I will need to do this with a for loop, I'...
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
Use the FILTER function (available in Excel 2021 and Microsoft 365) to find duplicates. Obtain the outcome in an array format by combining FILTER and UNIQUE functions. Enter the following formula in cell E6:=UNIQUE(FILTER(B6:B19,COUNTIF(C6:C17,B6:B19)>0))...