publicclassSolution {publicIList<int> FindDuplicates(int[] nums) {intsum =0; IList<int> result =newList<int>();for(inti =0; i<nums.Length; i++) {intindex = Math.Abs(nums[i])-1;if(nums[index]<0) { result.Add(Math.Abs(nums[i])); }else{ nums[index]= (-1)*nums[index];...
public: vector<int> findDuplicates(vector<int>& nums){ vector<int> res; for(inti = 0; i < nums.size(); i++){ intidx =abs(nums[i])-1; if(nums[idx] < 0) res.push_back(idx+1); nums[idx] = -nums[idx]; } returnres; } }; classSolution2{ public: vector<int> findDuplica...
classSolution {publicList<Integer> findDuplicates(int[] nums) {//initializationList<Integer> result =newArrayList<Integer>();//for loop: get the new index, add to result if negative, change to negativefor(inti = 0; i < nums.length; i++) {//get the new indexintindex = Math.abs(nums...
To find which elements are duplicates, you could use this “array without duplicates” we got, and and remove each item it contains from the original array content:const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = ...
442. Find All Duplicates in an ArrayMedium Topics Companies Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that ...
I need to load an array with random integers, however, the numbers need to be unique. The size of the array can vary based on user input, so using a static "if array[0] == array[1]", etc., is not going to work. I'm assuming I will need to do this with a for loop, I'...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime?
Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: Input: [4,3,2,7,8,2,3,1] Output: [2,3] 这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find ...