publicclassSolution {publicIList<int> FindDuplicates(int[] nums) {intsum =0; IList<int> result =newList<int>();for(inti =0; i<nums.Length; i++) {intindex = Math.Abs(nums[i])-1;if(nums[index]<0) { result.Add(Math.Abs(nums[i])); }else{ nums[index]= (-1)*nums[index];...
public: vector<int> findDuplicates(vector<int>& nums){ vector<int> res; for(inti = 0; i < nums.size(); i++){ intidx =abs(nums[i])-1; if(nums[idx] < 0) res.push_back(idx+1); nums[idx] = -nums[idx]; } returnres; } }; classSolution2{ public: vector<int> findDuplica...
https://leetcode.com/problems/find-all-duplicates-in-an-array/ 典型的数组中的重复数。这次是通过跳转法,一个个跳转排查的。因为查过的不会重复处理,所以复杂度也是O(n)。 后面发现了别人一个更好的做法。。。如下: public class Solution { // when find a number i, flip the number at position i...
C# programm to count the number of duplicates in given string C# programming - for the microcontroller STM32 C# Programming for both 32Bit Microsoft Access and 64Bit Microsoft Access C# Progress bar - How do i pass text message in progress percentage bar C# projects output unwanted BouncyCastle ...
LeetCode——Find All Duplicates in an ArrayQuestion Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime...
console.log(find_duplicate_in_array([1, 2, -2, 4, 5, 4, 7, 8, 7, 7, 71, 3, 6])); Output: ["4","7"] Flowchart: ES6 Version: // Function to find duplicates in an array const find_duplicate_in_array = (arra1) => { ...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
To find which elements are duplicates, you could use this “array without duplicates” we got, and and remove each item it contains from the original array content:const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = ...
[2,3] Java版,44 ms 19% 不是很好,猜测是因为排序了,而且没有充分利用只重复2次的特性。 classSolution{publicList<Integer>findDuplicates(int[]nums){List<Integer>newList=newArrayList<Integer>();// creating a new Listif(nums.length==0)returnnewList;Arrays.sort(nums);//O(logn)intpoint=0;inti...
LeetCode-442. Find All Duplicates in an Array 文章分类 Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appeartwiceand others appearonce. Find all the elements that appeartwicein this array. Could you do it without extra space and in O(n) runtime?