publicclassSolution {publicIList<int> FindDuplicates(int[] nums) {intsum =0; IList<int> result =newList<int>();for(inti =0; i<nums.Length; i++) {intindex = Math.Abs(nums[i])-1;if(nums[index]<0) { result.Add(Math.Abs(nums[i])); }else{ nums[index]= (-1)*nums[index];...
public: vector<int> findDuplicates(vector<int>& nums){ vector<int> res; for(inti = 0; i < nums.size(); i++){ intidx =abs(nums[i])-1; if(nums[idx] < 0) res.push_back(idx+1); nums[idx] = -nums[idx]; } returnres; } }; classSolution2{ public: vector<int> findDuplica...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Example: ...
classSolution {publicList<Integer> findDuplicates(int[] nums) {//initializationList<Integer> result =newArrayList<Integer>();//for loop: get the new index, add to result if negative, change to negativefor(inti = 0; i < nums.length; i++) {//get the new indexintindex = Math.abs(nums...
To find which elements are duplicates, you could use this “array without duplicates” we got, and and remove each item it contains from the original array content:const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = ...
442. Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. 首先是笨方法,超时 网上看的解法,其实就是用-1去标......
I need to load an array with random integers, however, the numbers need to be unique. The size of the array can vary based on user input, so using a static "if array[0] == array[1]", etc., is not going to work. I'm assuming I will need to do this with a for loop, I'...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
Find duplicates in an array in C# Rate this post Submit Rating Average rating4.89/5. Vote count:27 Submit Feedback Thanks for reading. To share your code in the comments, please use ouronline compilerthat supports C, C++, Java, Python, JavaScript, C#, PHP, and many more popular programmin...