这道题给了我们一个数组,数组中的数字可能出现一次或两次,让我们找出所有出现两次的数字,由于之前做过一道类似的题目Find the Duplicate Number,所以不是完全无从下手。这类问题的一个重要条件就是1 ≤ a[i] ≤ n (n = size of array),不然很难在O(1)空间和O(n)时间内完成。首先来看一种正负替换的方法...
Similar to find loop in li...[leetcode]-287. Find the Duplicate Number(C语言) Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, fi.....
Given an arraynumscontainingn+ 1 integers where each integer is between 1 andn(inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one. 给一个数组,其中一定有且只有一个数字是重复的,找出那个数字; O(n2)的算法就...
You must not modify the array (assume the array is read only). You must use only constant, O(1) extra space. Your runtime complexity should be less thanO(n2). There is only one duplicate number in the array, but it could be repeated more than once 非常好的题目,开始是用二分做的,比...
Find the Duplicate Number数组中重复的数 题意:数组中有1+n个数都是1到n之间,找出其中重复的。 解法一:二分搜索,先求出中点mid,然后遍历整个数组,统计所有小于等于mid的数的个数,如果个数小于等于mid,则说明重复值在[mid+1, n]之间,反之,重复值应在[1, mid-1]之间。 解法二:利用快慢指针,思路和带环...
Note: You must not modify the array (assume the array is read only). You must use only constant, O(1) extra space. Your runtime complexity should be less than O(n2). There is only one duplicate number in the array, but it could be repeated more than once. ...
- There is only one duplicate number in the array, but it could be repeated more than once. 代码如下: publicintfindDuplicate(int[] nums) {if(nums.length >1){intslow = nums[0];intfast = nums[nums[0]];//以下为求两个指针第一次相遇的点while(slow != fast){ ...
Method 2 – VBA Code to Find Duplicate Rows in Excel for Unique Cell Values OnlySteps:Bring up the Module window as shown in method 1. Type the following code.Sub DuplicateRows2() Dim cRange As Range Dim cCell As Range Set cRange = Range("B5:D10") For Each cCell In cRange If ...
Can you solve this real interview question? Find the Duplicate Number - Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive. There is only one repeated number in nums, return this repeated number
287 Find the Duplicate Number 寻找重复数 一个长度为 n + 1 的整形数组,其中的数字都在 1 到 n 之间,包括 1 和 n ,可知至少有一个重复的数字存在。假设只有一个数字重复,找出这个重复的数字。 注意: 不能更改数组内容(假设数组是只读的)。 只能使用恒定的额外空间,即要求空间复杂度是 O(1) 。