1classSolution {2publicList<String>findAndReplacePattern(String[] words, String pattern) {3List<String> res =newArrayList<>();4for(String word : words) {5if(helper(word, pattern)) {6res.add(word);7}8}9returnres;10}1112privatebooleanhelper(String word, String pattern) {13HashMap<Characte...
https://leetcode.com/problems/find-and-replace-pattern/ https://leetcode.com/problems/find-and-replace-pattern/discuss/161266/JAVA-3ms-Clear-Code https://leetcode.com/problems/find-and-replace-pattern/discuss/161288/C%2B%2BJavaPython-Normalise-Word [LeetCode All in One 题目讲解汇总(持续更新中...
Runtime: 60 ms, faster than 99.18% of JavaScript online submissions for Find and Replace Pattern. Memory Usage: 35.1 MB, less than 54.17% of JavaScript online submissions for Find and Replace Pattern.
A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word. (Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two...
890. Find and Replace Pattern 问题传送门 分析 我们只用模拟匹配替换过程即可,需要注意的是我们在匹配过程中需要使用两个map,来保证A -> B和B ->A的一致性。 代码...890. Find and Replace Pattern - LeetCode 为什么80%的码农都做不了架构师?>>> Question 890. Find and Replace Pattern Solution ...
原题链接在这里:https://leetcode.com/problems/find-and-replace-pattern/ 题目: You have a list ofwordsand apattern, and you want to know which words inwordsmatches the pattern. A word matches the pattern if there exists a permutation of letterspso that after replacing every letterxin the pa...
890. Find and Replace Pattern 思路 1. 用一个map加上set。map用来记录对应关系,set用来记录pattern中的字符是否已经建立了对应关系,然后遍历字符,先看map中是否有对应关系,没有对应关系就建立对应关系(建立对应关系之前,判断set中是否已经有对应字符,如果有,则证明之前已经有一组关系了,返回失败),如果map中有对应...
LeetCode 890. Find and Replace Pattern 2019-12-04 07:01 −原题链接在这里:https://leetcode.com/problems/find-and-replace-pattern/ 题目: You have a list of words and a pattern, and you want to know which w... Dylan_Java_NYC ...
https://leetcode.com/problems/find-and-replace-in-string/description/ Example: 题目给出的例子如下所示 Solution: 解题思路: (1)遍历S字符串的每个位置,在indexes数组中查找该位置是否需要进行替换,如果不需要,则将temp += S中对应字符。 (2)如果S字符串的某个位置在indexes数组中可以查找到,则比较从该起...
leetcode890---find and replace pattern打败100% 你有一个单词列表 words 和一个模式 pattern,你想知道 words 中的哪些单词与模式匹配。 如果存在字母的排列 p ,使得将模式中的每个字母 x 替换为 p(x) 之后,我们就得到了所需的单词,那么单词与模式是匹配的。 (回想一下,字母的排列是从字母到字母的双射...