The function used here is from the leetcode. Details can be found in leetcode problem:Implement strStr() The best explanation should be made in the comments, which can be understood by the leading of code. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 2...
给2个字符串,找到字符串A需要重复的次数,使得字符串B是字符串A的子串,如果没有答案,则返回-1。 解法1: Brute fore. a modified version of string find, which does not stop at the end of A, but continue matching by looping through A 解法2: KMP, O(n + m) version that uses a prefix table...
⛽️「算法通关手册」:超详细的「算法与数据结构」基础讲解教程,从零基础开始学习算法知识,850+ 道「LeetCode 题目」详细解析,200 道「大厂面试热门题目」。 - Update 03.String-KMP.md · itcharge/LeetCode-Py@62c7e76
41 changes: 20 additions & 21 deletions 41 Contents/06.String/02.String-Single-Pattern-Matching/04.String-Boyer-Moore.md Original file line numberDiff line numberDiff line change @@ -1,8 +1,8 @@ ## 1. BM 算法介绍 ## 1. Boyer Moore 算法介绍 BM 算法的全称叫做 **「Boyer Moore 算法...
“ int QStringList::indexOf(const QString & value, int from = 0) const Returns the index position of the first occurrence of value in the list, searching forward from index position from. Returns -1 if no item matched. “ 具体测试: ...
Input:s = "Let's take LeetCode contest"Output:"s'teL ekat edoCteeL tsetnoc" Example 2 Input:s = "God Ding"Output:"doG gniD" Solution 1 (Using Loop) publicclassSolution{publicstringReverseWords(strings){string[]array=s.Split(" ");stringnewString="";if(array.Length>0){for(intai=0...
View Code 43. Multiply Strings (medium) 字符串代表的两个数相乘,返回字符串 problem View Code 44. Wildcard Matching (hard) # 通配正则表达式:*和? problem View Code View Code 49. Group Anagrams (medium) 字符串分组,组成元素一致的分为一组 ...
【LeetCode】字符串 string(共112题) 【3】Longest Substring Without Repeating Characters(2019年1月22日,复习) 【5】Longest Palindromic Substring(2019年1月22日,复习) 【6】ZigZag Conversion(2019年1月22日,复习) 【8】String to Integer (atoi)(2019年1月22日,复习)...
\begin{Code} // LeetCode, Implement strStr() // 暴力解法,时间复杂度O(N*M),空间复杂度O(1) class Solution { public: int strStr(const string& haystack, const string& needle) { if (needle.empty()) return 0; const int N = haystack.size() - needle.size() + 1; for (int i...
随笔分类 -leetcode-string Evaluate Reverse Polish Notation 摘要:1 public class Solution { 2 public int evalRPN(String[] tokens) { 3 String operations ="+-*/"; 4 Stack stack = new Stack(); 5 for(String s:tokens){ 6 if(!operations.contains(s)){ 7 stack.push(s); 8 } 9 else{10...