classSolution {publicList<Integer> findDuplicates(int[] nums) {//initializationList<Integer> result =newArrayList<Integer>();//for loop: get the new index, add to result if negative, change to negativefor(inti = 0; i < nums.length; i++) {//get the new indexintindex = Math.abs(nums...
时间复杂度:O(n),空间复杂度:O(n) funcfindDuplicates(nums []int)[]int{len:=len(nums);iflen<=1{returnnil} hashMap :=make(map[int]int) result := []int{}for_, v :=rangenums { _, exist := hashMap[v];if(exist) { result =append(result, v) }else{ hashMap[v] = v } }ret...
leetcode算法: Find All Duplicates in an Array Given an array of integers, 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements that appear twice in this array. Could you do it without extra space and in O(n) runtime? Exa...
442. Find All Duplicates in an ArrayMedium Topics Companies Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice. You must write an algorithm that ...
442. Find All Duplicates in an Array 题目描述: Given an array of integers, 1 ≤ a[i] ≤n(n= size of array), some elements appeartwiceand others appearonce. Find all the elements that appeartwicein this array. Could you do it without extra space and in O(n) runtime?
详见:https://leetcode.com/problems/find-all-duplicates-in-an-array/description/ C++: 方法一: AI检测代码解析 classSolution{public:vector<int>findDuplicates(vector<int>&nums){vector<int>res;for(inti=0;i<nums.size();++i){intidx=abs(nums[i])-1;if(nums[idx]<0){res.push_back(idx+1);...
问题描述: Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array),some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this ar... 查看原文 leetcode之Find All Duplicates in an Array 问题 问题描述: ...
const yourArray = [1, 1, 2, 3, 4, 5, 5] const yourArrayWithoutDuplicates = [...new Set(yourArray)] let duplicates = [...yourArray] yourArrayWithoutDuplicates.forEach((item) => { const i = duplicates.indexOf(item) duplicates = duplicates .slice(0, i) .concat(duplicates.slice(i...
Finally, the last method to find duplicates in an array is to use the for loop.Here is an example that compares each element of the array with all other elements of the array to check if two values are the same using nested for loop:...
Learn how to find duplicate values in a JavaScript array with this comprehensive guide, including examples and step-by-step instructions.