arpit.java2blog.generic; public class FindSecondLargestMain { public static void main(String args[]) { int[] arr1={7,5,6,1,4,2}; int secondHighest=findSecondLargestNumberInTheArray(arr1); System.out.println("Se
In this tutorial, Java program to find the largest number in array. Here is simple algorithm to find larget element in the array. Initialize lrg with arr[0] i.e. first element in the array. If current element is greater than lrg, then set lrg to current element. 1 2 3 4 5 6 7 ...
Java program to find the maximum element of an array using recursion. classRecursiveMax{publicstaticvoidmain(String[]args){int[]arr={10,5,7,9,15,6,11,8,12,2,3};intmax=recursiveMax(arr, arr.length);System.out.println("Maximum element: "+max);}staticintrecursiveMax(int[]arr,intlength...
Write a Java program to find the number of even and odd integers in a given array of integers. Pictorial Presentation: Sample Solution: Java Code: // Import the java.util package to use utility classes, including Arrays.importjava.util.Arrays;// Define a class named Exercise27.publicclassExe...
Java Code: // Import necessary Java libraries.importjava.util.*;importjava.lang.*;// Define a class named Main.publicclassMain{// The main method for executing the program.publicstaticvoidmain(String[]args){// Define an array of integers.intnums[]={6,7,9,16,25,12,30,40};intn=nums...
Find largest number from three integer number in Java: This program will read three integer number from the keyboard and find the largest number.Find largest among three numbers using Java Program//Java program to find largest number among three numbers. import java.util.*; class LargestFrom3 ...
In this Java tutorial, you will learn How to Find Maximum Occurrence of Words from given Text File? Here is a logic for getting top element: Create a
Learn how to find the largest, smallest, second largest, and second smallest numbers in a list using Python programming.
Make every integer less than 1 or more than n to 1 while traversing the array again since the largest possible answer can be n+1, where n is the size of the input array. After this again traverse the array. This time for every ith number we will update the value of a[(a[i]-1)...
(mid, right)). If the second max elements in the entire array and the second max element in the 2nd half of the array are equal (i.e.smax_all == smax_2nd), then the maximum element in the array must be in the second half, hence replace theleftpointer with themid...