6x2+8x+9x+12 Step 5: Group the termsNow, we group the terms:(6x2+8x)+(9x+12) Step 6: Factor out the common factorsFrom the first group 6x2+8x, we can factor out 2x:2x(3x+4)From the second group 9x+12, we can factor out 3:3(3x+4) Step 7: Combine the factored terms...
Factorise :x4−7x2+1 View Solution Factorise: 8x2−72xy+12x View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium ...
(1) x3−6x2+11x−6= (2) x3+2x2−x−2= (3) x3+7x2+14x+8= (4) x3−3x2−10x+24= (5) x3+2x2−13x+10= 相关知识点: 试题来源: 解析 (1) (x−1)(x−2)(x−3) (2) (x+1)(x+2)(x−1) (3) (x+1)(x+2)(x+4) (4) (x+3)(x−2)(x−4...
百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
结果1 题目5 Factorise completely.x^2-6x 3x(3x-2)Answer...。[2] 相关知识点: 试题来源: 解析 3x(3x-2)final answerB1 for x(9x-6) or 3(3x²-2x) 反馈 收藏
=x(x + y) + 8(x + y)=(x + y)(x + 8) (2)15xy - 6x +5y - 2 = 3×5×x×y-3×2×x×5xy-2= 3x (5y - 2) +1(5y - 2)= (5y - 2) (3x +1) (3)ax + bx- ay - by = a × x + b × x - a × y - b × y=x(a + b) - y(a + ...
Factor the given polynomial completely: 42 + a - a^2 Factor the given polynomial: 2xy + 6x - y - 3 Factor the given polynomial: 15x^2 - 18x - 24 Factor the given polynomial: 35p^2 + 13p - 4 Factor the given polynomial: x^2 + 8x + 12 Factor the given polynomial:...
百度试题 结果1 题目Hence, factorise fully x^3-6x^2-x+6 相关知识点: 试题来源: 解析 =(x-1)(x²-5x-6)=(x-1)(x+1)(x-6) 反馈 收藏
12x+20y 8x+4x+22y–2y 12x–6y+26y 8x+6x–2x+22y–2yCompleteyourdiagram Lettersfornumbers:a+b=10,whatcouldaandbbe?ifa=2,b=8whatisa+b?ifa=25,b=5whatisa+b?Letters,numbersandarea 6 2 b 5 Area?2x6=12 Area?5xb=5b Letters,numbersandarea 4 a 4 a Area?4x4=16Area?axa=a2 Lette...
Factorise: x^2-32xy-105y^2 03:45 Factorise: x^2 +21x+108 04:28 Factorise: 6x^2+7x-3 03:41 Factorise: 42 x^2+10x-12 02:59 Factorise: 12y^2y-6 00:32 Factorise: x^2-10x+21. 02:30 Carry out the following divisions: 6x^3 -: 2x. 00:50 Carry out the following divisions:...