We can rewrite the polynomial by splitting the middle term 17x into 8x+9x:6x2+8x+9x+12 Step 5: Group the termsNow, we group the terms:(6x2+8x)+(9x+12) Step 6: Factor out the common factorsFrom the first group 6x2+8x, we can factor out 2x:2x(3x+4)From the second group 9x...
Factorise: x^2-32xy-105y^2 03:45 Factorise: x^2 +21x+108 04:28 Factorise: 6x^2+7x-3 03:41 Factorise: 42 x^2+10x-12 02:59 Factorise: 12y^2y-6 00:32 Factorise: x^2-10x+21. 02:30 Carry out the following divisions: 6x^3 -: 2x. 00:50 Carry out the following divisions:...
结果1 题目5 Factorise completely.x^2-6x 3x(3x-2)Answer...。[2] 相关知识点: 试题来源: 解析 3x(3x-2)final answerB1 for x(9x-6) or 3(3x²-2x) 反馈 收藏
百度试题 结果1 题目(b) Factorise fully 6x^3-27x^2+30x=3x(2x2-9x+10) [M1]=3x(2x-5)(x-2) 相关知识点: 试题来源: 解析 =3x(2x²-9x+10) [M1] = 3x(2x-5)(x-2) 反馈 收藏
(i) x^(2)+9x+18=x^(2)+6x+3x+18 {by splitting middle term] =x(x+6)+3(x+6)=)x+3(x+6) (ii) 6x^(2)+7x-3=6x^(2)+9x-2x-3 [by splitting middle term] (iii) 2x^(2) -7x -15=2x^(2) -10x+3x-15 [by splitting middle term] =2x(x-5)+3(x-5)=(2x+3)(x-5)
Analyze the roots of the following equations: (i)2x3−9x2+12x−(9/2)=0 (ii)2x3−9x2+12x−3=0 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium ...