Factorise : x^(3)+(1)/(x^(3))-2x-(2)/(x) 02:16 Factorise : 8a^(3)-b^(3)+1+6ab 01:42 Factorise : a^(6)+32a^(3)-64 03:20 Factorise : x^(3)+y^(3)-12xy+64 01:18 Factorise : (2x-y)^(3)-(x+y)^(3)+(2y-x)^(3) 03:42 Factorise : a^(3)+(1)/(a^...
such that a + b =5 and ab = 6. on solving this we obtain, a = 3 and b = 2 thus, the above expression can be written as: x 2 + 3x + 2x + 6 = x(x + 3) + 2(x + 3) = (x + 3)(x + 2) thus, x+3 and x+2 are the factors of the polynomial x 2 + 5x + ...
百度试题 结果1 题目16 Factorise 6x^2+7x-20 .(3x-4)(2x+5) final answer..[2] 相关知识点: 试题来源: 解析 (3x-4)(2x+5) final answerB1 for (ax+b)(cx+d) where ac=6andad+bc=7 or bd=-20 反馈 收藏