例如,对于$x^3 + 3x^2 + 3x + 1$,可以将其分组为$(x^3 + 3x^2) + (3x + 1)$,然后利用公式法和提取公因式进行分解。 因式分解在解决数学问题中的应用 因式分解在解决数学问题中具有广泛应用。在代数方程中,通过因式分解可以将方程转化为更简单的形式,便于求解。在不等式证明中,...
Factorise : - 2x^(2)+7x+3 01:09 Factorise (Using factor theorem ) : 3x^(3)-7x^(2)+8x-12 02:16 Factorise: x^(2) -7x+12 03:49 Factorise: x ^(2) - 7x- 30 01:28 Factorise the following algebraic expressions 3x^2+7x-6 . 01:40Exams...
Factorise x2+1x2−3. A(x−1x+a)(x+1x−1) B(x+1x+a)(x−1x−1) C(x−1x+a)(x−1x+1) D(x−1x+a)(x−1x−1)Submit Question 2 - Select One Factorise: 3x2−48 A3(x−4)(x−4) B3(x+4)(x+4) C3(x+4)(x−4) Dnone of theseSubmit Questi...
百度试题 结果1 题目Factorise2x^2+3x-5(2x+5)(x-1) 相关知识点: 试题来源: 解析 (2x+5)(x-1) 反馈 收藏
(x 2 -1) (x+1) solved examples question 1: check whether x+3 is a factor of x 3 + 3x 2 + 5x +15. solution: let x + 3= 0 => x = -3 now, p(x) = x 3 + 3x 2 + 5x +15 let us check the value of this polynomial for x = -3. p(-3) = (-3) 3 + 3 (-3...
x=-1 [Let find the factors of 3 which will make 4 (coefficient of x)]3=3* 1 [3+1=4]. Hence 3x+x=4x, then(split)x^2+4x+3&=x^2+3x+x+3 &=x(x+3)+1(x+3) &=(x+3)(x+1)(split)Solving (x+3)(x+1)=0, either(x+3)=0, then x=-3 or (x+1)=0, then x=...
(1)Solution:x2 xy 8x 8y = x × x x × y 8 × x 8 × y=x(x y) 8(x y)=(x y)(x 8) (2)15xy - 6x 5y - 2 = 3×5×x×y-3×2×x×5xy-2= 3x (5y - 2) 1(5y - 2)= (5y - 2) (3x 1) (3)ax bx- ay - by = a × x b × x - a ...
5. Factorise:(a) x^3+1/(x^3) (b) a^3-1/(b^3) () (a^3)/(27)+(b^3)/(64) (d) (x^3)/(27)-(125)/(y^3) () (27x^3)/(64)+1 相关知识点: 试题来源: 解析 c)( (C (a/3+a/4)((a^2)/9-(ab)/(12)+(b^2)/(16)) e) (-(3x)/4+1...
Rewrite the x coefficients as the sum of 6 and -1 to get: 3x² + (6-1) x -2. Step 4 Distribute the x to both 6 and -1 and get: 3x² + 6 x -x -2. Then factor by grouping: 3x(x+2) + (-1) (x+2) = (3x-1) (x +2). This is the final answer. ...
4(x+3)(x-3)(8+a)(8-a)(6(y+x)(y-x)3x(x+3)(x-3)8(2y+x)(2y-x)(4x+7y^2)(4x-7y^2) 10 2y(x-y) 结果一 题目 II. Fill in the blanks4 Factorise: x2-9 =Factorise:64-a^2=6F Factorise_2-x^2+y^2=Factorise: 3x^3-27x=3 Factorise: -x^2+4y^2=8Factorise: 16...