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Factorise (Using factor theorem ) : 36-7x^(2)-x^(3) 03:37 Factorise (Using factor theorem ) : 3x^(3)-7x^(2)+8x-12 02:16 Factorise the following: x^(3)-2x^(2)-5x+6 02:38 Factorise (Using factor theorem ) : a^(3)-7a^(2)+7a+15 03:16 Factorise (Using factor theorem ...
We have to factorise: {eq}x^3 + 2x^2 + 3x + 6 {/eq}. $$\begin{align} x^3 + 2x^2 + 3x + 6 &=(x^3 + 2x^2) + (3x + 6 ) \ & \left [ \text{Break the... Learn more about this topic: How to Teach Factoring ...
百度试题 结果1 题目Factorise x2Facorisex^2+3x +x(x+3) 相关知识点: 试题来源: 解析 x(x+3) 反馈 收藏
结果1 题目5 Factorise completely.x^2-6x 3x(3x-2)Answer...。[2] 相关知识点: 试题来源: 解析 3x(3x-2)final answerB1 for x(9x-6) or 3(3x²-2x) 反馈 收藏
Factorise:25x2−9. Question: Factorise:25x2−9. Algebraic Identities: The quadratic expression that is given to factorize is set up in the form of the difference of two perfect squares. So, here we will apply the algebraic identities to factorize the given expression. The basic algebraic...
Factorisez3x23x2à partir de−3x2-3x2. 3x2(4x)+3x2(−1)=03x2(4x)+3x2(-1)=0 Factorisez3x23x2à partir de3x2(4x)+3x2(−1)3x2(4x)+3x2(-1). 3x2(4x−1)=03x2(4x-1)=0 12x3−3x2=012x3-3x2=0 ( )
Distribute the x to both 6 and -1 and get: 3x² + 6 x -x -2. Then factor by grouping: 3x(x+2) + (-1) (x+2) = (3x-1) (x +2). This is the final answer. Step 5 Check the answer by multiplying the binomials (3x-1) (x +2) and compare to the quadratic equation ...
5. Factorise:(a) x^3+1/(x^3) (b) a^3-1/(b^3) () (a^3)/(27)+(b^3)/(64) (d) (x^3)/(27)-(125)/(y^3) () (27x^3)/(64)+1 相关知识点: 试题来源: 解析 c)( (C (a/3+a/4)((a^2)/9-(ab)/(12)+(b^2)/(16)) e) (-(3x)/4+1...
=x(x + y) + 8(x + y)=(x + y)(x + 8) (2)15xy - 6x +5y - 2 = 3×5×x×y-3×2×x×5xy-2= 3x (5y - 2) +1(5y - 2)= (5y - 2) (3x +1) (3)ax + bx- ay - by = a × x + b × x - a × y - b × y=x(a + b) - y(a + ...