解答:提取公因式2,得到$2(x^2 - 2x + 1)$。然后利用完全平方公式,得到$2(x - 1)^2$。 将多项式$x^2 + 4x - 5$进行因式分解。 解答:利用十字相乘法,找到两个数-1和5,它们的和等于4,它们的积等于-5。然后将其与多项式的一次项和常数项组合,得到$(x - 1)(x + 5)$。...
Factorise x^3 + 7x^2 + 2x - 40. View Solution Factorize 6x2+7x−3. View Solution Factorise : - 2x2+7x+3 View Solution गुणनखण्ड कीजिए : 6x2+7x−3 View Solution Factorise: 6x2−17x−3 View Solution 6x2−7x−3 शून्य...
Factorise: 2x^3-x^2-13x-6 03:12 Factorise: (i) x^3-2x^2-x+2 (ii) x^3-3x^2-9x-5 (iii) x^3+13 x^2+3... 07:57 13x^(2)+9(x+1)-(2x+3)(x+2)=6 01:33 Factorise: 2x^3-x^2-13x-6 03:12 Evaluate: lim(x rarr -2) (2x^(3)-x^(2)-13x-6)/(3x^(2)...
x 2 + 3x + 2x + 6 = x(x + 3) + 2(x + 3) = (x + 3)(x + 2) thus, x+3 and x+2 are the factors of the polynomial x 2 + 5x + 6. roots of polynomials multiplying polynomials zeros of polynomials polynomials class 9 polynomial for class 10 practice questions 1. factorise...
Factor the given polynomial: x^2 + 7x - 8 Factor the given polynomial: x^4 + 2x^2 - 9x^2 - 18 Factor the given polynomial: u^2 - 6u - 16 Factor the given polynomial: xy - 4x - y + 4 Factor the given polynomial: 35a^2 + 3a - 20 ...
(3) x3+7x2+14x+8= (4) x3−3x2−10x+24= (5) x3+2x2−13x+10= 相关知识点: 试题来源: 解析 (1) (x−1)(x−2)(x−3) (2) (x+1)(x+2)(x−1) (3) (x+1)(x+2)(x+4) (4) (x+3)(x−2)(x−4) (5) (x+5)(x−1)(x−2) (1)略(2)略(3)...
相关知识点: 试题来源: 解析 , (2/I+x) ⑦ 5 (1/2x-1)^2 6 (2x-1)^2 7 (xy-2)^2 8 (3-2t)^2 q 2x;2x+5 y 10 4m^2n^2 ; 2mm+ 1 反馈 收藏
8(a) Factorise.(i)6x+93(2x-3) Final answer(a)(i)[1](ii)2ax+3a(ii)a(2x+3) Final answer
3ab+62;a+b,b-c-|||-4-|||-axb;ax-b;x+1 52ax-ay;4bx-2by;2x--|||-y;a+26 6x2;a2+2ab+62;x+a+b;x--|||-a-b7(a+b)(a-b+x)8(y-1)(x1) 结果一 题目 II. Fill in the blanksFactorise:ab+b^2-ac-bc=()-() 4 Factorise:ax^2+ax-b-bx=()=() 5 Facto...
II. Fill in the blanks4)m^2+m+()=()^225Factorise: 49a^2-36=6Fatose: 1/4y^2+y+1=7Factorise: (x+y)^2+6(x+y)+9==8Factorise: (x^2+2x)^2+2(x^2+2x)+1=9 Factorise: x^3-6x^2+9x=10 Factorise: x^2+2x+1-y^2= ...