View Solution Factorise :x4+y4−2x2y2 View Solution Free Ncert Solutions English Medium NCERT Solutions NCERT Solutions for Class 12 English Medium NCERT Solutions for Class 11 English Medium NCERT Solutions for Class 10 English Medium NCERT Solutions for Class 9 English Medium ...
Factorize completely. 4a^4 b^2 - 8a^3b^2 + 12a^3b Factorize: 4 x^2 y + 8 x y. Factorize 4 x^3 - 5 x^2 + 7 x - 6. Factorize: 2x^2 + 10x Factorize. 8s^2 - 2s - 3 Factorize 8 x^3 + y^3 + 12 x^2 y + 6 x y^2. ...
Factorise each of the following quadratic expressions completely.(a) 4x^2-16(b) 75-12p^2(c) 2x^2+10x+12(d) 3x(2x-11)+15 相关知识点: 试题来源: 解析(a)4x2-16=4(x2-4) 1,4 =u(x^2-2^2) 4 and 16=4 4c2(2) Pifference between 2 squares (b) 72-12P^2=3125-4P^2 =3[...
百度试题 结果1 题目Factorise fully the following:a)2x+8b)3x-12c) 6x +4d)18x-9 相关知识点: 试题来源: 解析 e0 2x+8=2(x+4) b) 3x-12= 3(x-4) 6x+4= 2(3x+2) 27 18x-9= 9(2x-1) 反馈 收藏
x 2 + 3x + 2x + 6 = x(x + 3) + 2(x + 3) = (x + 3)(x + 2) thus, x+3 and x+2 are the factors of the polynomial x 2 + 5x + 6. roots of polynomials multiplying polynomials zeros of polynomials polynomials class 9 polynomial for class 10 practice questions 1. factorise...
(x2+1)2=x4+2x2+1So, we subtract x2 to get:x4+x2+1=(x2+1)2−x2 Step 4: Apply the difference of squaresNow we can apply the identity a2−b2=(a−b)(a+b):Let a=x2+1 and b=x:(x2+1−x)(x2+1+x) Step 5: Simplify the factorsNow we simplify the two factors...
(a+b)2=a2+2ab+b2(a−b)2=a2−2ab+b2a2−b2=(a+b)(a−b) Answer and Explanation:1 We have to Factorise:25x2−9. We will apply the algebraic identities to factorize the given expression: $$\begin{align} 25x^2 - 9... ...
4.(a)Factorise, as far as possible, the expression x^3+x^2-2x (b) Hence sketch the function y=x^3+x^2-2x 相关知识点: 试题来源: 解析 (a) x(x^2+x-2)=x(x+2)(x-1) (b) (a)Also check your answer by multiplying out to get back to original expression(b)Intersections wi...
16 Factorise completely(a) 4x^2-10x-6 ,(b) 10x^2y-5xy+2x-1 . 相关知识点: 试题来源: 解析 (a)4x-10x-6.=2(2'-5x-3)[M시=2(2x+I)(x-3)(4)(b)10x'y-$xy+2x-1.=Sx(2x-1)+1(2x-1)IM1)=(5xy+I)(2x-I)( 反馈 收藏 ...
- 16z2=(4z)2 So we can rewrite the expression as: (2x)2+(3y)2+(4z)2+12xy−24yz−16xz 2. Identify the terms for factorization: We need to recognize that we can use the identity: (a+b+c)2=a2+b2+c2+2(ab+bc+ca) Here, we can identify: - a=2x - b=3y - c=−4...