Example 1Factor x2+ 7x + 12. Solution We look for two integers whose product is 12 and whose sum is 7. Consider the following pairs of factors whose product is 12. We see that the only pair of factors whose product is 12 and whose sum is 7 is 3 and 4. Thus, ...
(x+3)(x+4)① 12 can be factored as 1×12, 2×6 and 3×4.pq=12,so p and q can be 1 and 12, 2 and 6 or 3 and 4.p+q should be equal to 7, so when p and q are 3 ane 4, p+q=7.Thus, x2+7x+12=(x+3)(x+4).②1×4+1×3=7,thus, x2+7x+12=(x+3)(x...
Ex: Polynomial Division of (x^4+2x+8)/(x+6) The given expression is (x^4+2x+8)/(x+6) The Divident is x^4 + 2 x + 8 and Divisor is x + 6 x + 6)x^4 + 2 x + 8(x^3 - 6 x^2 + 36 x - 214 - x^4 - 6 x^3 --- ...
A container van has thefunctionV (x) = 2x3-7x2+ 2x + 3, where x is the length of the container and (x-3) is a factor of the function. If, for instance, x=12, how do you calculate the container van’s dimensions? This situation is an illustration of a real–world application ...
How to factor binomials in the form of (x^3+b^3): Just plug into (a - b) (a^2 +ab + b^2). For example, (x^3 + 8) = (x - 2) (x^2 + 2x + 4). How to factor binomials in the form of (x^3-b^3): Plug into (a + b) (a^2 - ab + b2). Note that the...
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(x) when studying the modified Pschl-Teller potential and the single ring-shaped potential.We present the evaluations of the integrals involving the universal associated Legendre polynomials and the factor(1-x~2)~(-p-1) as well as some important byproducts of this integral which are useful ...
1x Glowstick(can be built from a test tube and bio scrap) 2x Glass Scraps(go break some windows if you don't have any handy) 2x Boxes of Screws(either find them or make them from metal scrap) 2x Desk Phones(loot offices to find these) ...
Factor the following polynomial completely: 15w^2 - 15w - 90 Factor the following polynomial completely: x^(3)y^(2) + 7x^(2)y^(2) - 18xy^2 Factor the polynomial completely: x^2 - 5x + 6 Factor the polynomial completely: 25x^3 - 1600y^3 ...
( x^3-7x^2-16x+112) 相关知识点: 试题来源: 解析 Factor out the greatest common factor from each group. ( x^2(x-7)-16(x-7)) Factor the polynomial by factoring out the greatest common factor, ( x-7). ( (x-7)(x^2-16)) Rewrite ( 16) as ( 4^2). ( (x-7)(x^2-4^...