自变量 x 的方差膨胀因子记为 VIF，它的计算方法为：VIFi=11−Ri2i=1,2,⋯,k ...
Example 2 Factor the expression x^3 -2x^2+5x. Solution: Each of the three terms contains the common factor x, hence, x^3 -2x^2+5x=x(x^2-2x+5) Note. In factoring exercises the student should always verify his results, by...
How do you factor x^2 - 3x + 15? How do you factor x^2 - 4x - 45? How do you factor x^2 + 4x - 6? How do you factor (-5t^2+50t+5)? How do you factor x^2 - 6x - 16? How do you factor x^4 + 2x^3 - 8x - 16?
We now see that 2x is a common monomial factor to all three terms. Then we factor 2x out of the polynomial, and write 2x( ) Now, we divide each term in the polynomial by 2x and write the quotients inside the parentheses to get 2x(2x2 - 3x + 1) We can check our answer in ...
Factor completely: 15xz + 15yz - 5xy - 5y2 Factor x^2 + 16. Factor: 7m + mn + 35 + 5n. Factor: 3 x^2 + 5 x - 2. Completely factor: 3j^3 -51j^2 +210j. Factor out 2x^4 + 3x^3 - 11x^2 - 9x + 15. Factor y= 6x^2 - 36. ...
解析 (1) (2x−3)(2x−5) (2) (3x+4)(9x−8)结果一 题目 【题目】Factor:(1) 4x^2-16x+15=(2) 27x^2+12x-32= 答案 【解析】(1)(2x-3)(2x -5)(2)(3x+4)(9x-8)相关推荐 1【题目】Factor:(1) 4x^2-16x+15=(2) 27x^2+12x-32= ...
The factors of 6x2 are x, 2x, 3x, 6x. The factors of 15 are 1, 3, 5, 15. Eliminate as too large the product of 15 with 2x, 3x, or 6x. Try some reasonable combinations. These would automatically give too large a middle term. ...
= −11.664−3.24+12.6+2 = −0.304 No, (x+1.8) is not a factor. We could try some other values near by and maybe get lucky. But at least we know (x−2) is a factor. Let us check using Polynomial Long Division: 2x2+3x−1 x−2)2x3− x2−7x+2 2x3−4x2 ...
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(i) Let f(x)=2x^4+3x^3+a(x^2+x)+b.2x^2+3x-2=(2x-1)(x+2)f(1/2)=0 and f(-2)=0 since (2x-1)(x+2) is a factor of f(x).Since f(1/2)=0,2(1/2)^4+3(1/2)^3+a|(1/2)^2+(1/2)+b=01/8+3/8+a(3/4)+b=01/2+3/4a+b=02+3a+4b=0……...