3 It is given that x-1 is a factor of f(x), where f(x)=x^3-6x^2+ax+ b .(i) Express b in terms of a.[2] (ii) Show that the remainder when f(x) is divided by x-3 is twice the remainder when f(x) is divided by x-2.[4] ...
结果1 题目【题目】Factor:(1)$$ a ^ { 2 } b - 2 a b + b = \_ $$(2)$$ x ^ { 3 } - 4 x = \_ $$(3)$$ m ^ { 3 } n - 9 m n = \_ \_ \_ $$(4)$$ 2 a ( x ^ { 2 } + 4 ) ^ { 2 } - 3 2 a x ^ { 2 } = \underline ...
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1、假定只有两个国家、两种商品、两种生产要素（劳动和资本）。这一假设目的是为了便于用平面图说明理论。2、假定两国的技术水平相同；即同种产品的生产函数相同。这一假设主要是为了便于考察要素禀赋，从而考察要素价格在两国相对商品价格决定中的作用。3、假定X产品是劳动密集型产品，Y产品是资本密集型产品。4、假定...
结果1 题目Given that x + I is a factor of 3x^3-14x^2-7x+ d . show that d=10.3i-11^3-1+i-1i^2-7i-1;+cl=0 with completion to d=10 相关知识点: 试题来源: 解析 3(-1)³-14(-1)²-7(-1)+d=0 with completion to d=10 ...
Factor( ((x-1))^(1/3)) out of ( ((x-1))^(2/3)).( ((x-1))^(1/3)((x-1))^(1/3)+((x-1))^(1/3))Multiply by ( 1).( ((x-1))^(1/3)((x-1))^(1/3)+((x-1))^(1/3)⋅ 1)Factor( ((x-1))^(1/3)) out of ( ((x-1))^(1/...
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简单来说,LFM是让模型直接输出两组值,一组输出作为未来因子的预测均值f_{\theta}(x),另一组作为预测方差g_{\theta}(x),为了训练网络参数\theta,我们采用极大似然的目标函数: \begin{aligned} \theta^{\mathrm{MLE}} &=\max _{\theta} \prod_{i=1}^{n} \frac{1}{\sqrt{2 \pi g_{\theta}\le...
综合上述,变量1,3,4归为一个因子 变量2,6,归为一个因子 变量5归为一个因子 这个数据集的6个变量降低维度到3个因子。 因子分析步骤: 1.因子分析假设条件 2.找到因子的方法 3.决定因子是否重要 4.检验因子里变量的交互性 因子分析假设 假设很重要,如果不符合假设条件,则报告可行性很差 ...