Excel VBA运行时错误“13”类型不匹配 、 ActiveCell.Offset(1, 0).Activate 这是我当前错误的代码错误是Excel VBA runtime error "13 type mismatch。错误所在的行:If ActiveCell.Value - ActiveCell.Offset(-1, 0).Value < 0 Then 此代码 浏览12提问于2017-07-28得票数 0 回答已采纳 6回答 Excel VBA...
当我将7,000替换为30000时，Excel VBA显示在VBA代码中，我们经常会看到类似于On Error Resume Next这样...
Executing VBA code and get Run-time error '13': Type mismatchCannot figure out why. Code is properly set up and looks just like examples on Microsoft Help. Copy of code below:Dim strKillFile As StringstrKillFile = "C:\Users\username\Documents\junk.txt"Kill strKillFile...
brr = Application.Transpose(Application.Index(arr, 0, C))0去掉试试看
Calling an RFC function module from Excel/VBA I am trying o pass an array of text strings to one of the tables of the unction module and I am getting Run-time error '13' which says "Type mismatch". In the following example 'myarray' is the array which has been defined as Dim my...
Pop out error: Run time error 13 Type Mismatch when executing macro. Error was displayed at this line of code below: Set successrng = Find(What:="Success", After:=ActiveCell, LookIn:=xlValues _ ...Show More excel Formulas and Functions Macros and VBA Like 0 Reply HansVogela...
I get the 'error 13 Type mismatch' error. Here is the code: prettyprint Sub UpdateBookmark(BookmarkToUpdate As String, TestToUse As String) Dim BMRange As Range Set BMRange = ActiveDocument.Bookmarks(BookmarkToUpdate).Range BMRange.Text = TextToUse ActiveDocument.Bookmarks.Add BookmarkTo...
1.6.3 VBA的参数传递参数传递的方式有两种,引用和传值。传值,只是将数据的内容给到函数,不会对数据本身进行修改。引用,将数据本身传给函数,在函数内部对数据的修改将同样的影响到数据本身的内容。参数定义时,使用ByVal关键字定义传值,子过程中对参数的修改不会影响到原有变量的内容。默认情况下,过程是按引用方式...
Discover how easy it is to assign a range to an array using Excel VBA. You will also learn how to avoid common errors, like run-time error 13 type mismatch.
Run-time error '13': Type Mismatch G: The maximum number of elements in the array is limited only by available memory. Also, you do not have to define the parameter as a Variant variable in the Excel macro. However, if you want to pass the array ByVal, you must define the parameter...