publicclassSolution{publicbooleancanPartition(int[] nums){// 数组求和intsum=Arrays.stream(nums).sum();// 场景1:和为奇数不能均分if(sum %2==1) {returnfalse; }inttarget=sum /2;intn=nums.length;boolean[][] dp =newboolean[n +1][target +1]; dp[0][0] =true;for(inti=1; i <= ...
[leetcode]416. Partition Equal Subset Sum Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. 给定一个非空数组,是否能把数组划分为两个和相等的子集。 Not......
1classSolution {2publicbooleancanPartition(int[] nums) {3intlen =nums.length;4intsum = 0;5intmax = 0;6for(intnum : nums) {7sum +=num;8max =Math.max(max, num);9}10inttarget = sum / 2;1112//corner case13if(sum % 2 == 1) {14returnfalse;15}16if(max >target) {17returnf...
每次遍历一遍DP,看sum/2处是否为true,为true时直接返回。 publicbooleancanPartition(int[]nums){if(nums==null||nums.length==0){returnfalse;}intsum=0;for(inti=0;i<nums.length;i++){sum+=nums[i];}if(sum%2==1){returnfalse;}boolean[]dp=newboolean[sum+1];dp[0]=true;for(intnum:nums)...
来自专栏 · LeetCode Description Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal. Note: Each of the array element will not exceed 100.The array size will not exceed 200...
https://leetcode.cn/problems/partition-equal-subset-sum 给你一个 只包含正整数 的 非空 数组 nums 。请你判断是否可以将这个数组分割成两个子集,使得两个子集的元素和相等。 示例1: 输入:nums = [1,5,11,5] 输出:true 解释:数组可以分割成 [1, 5, 5] 和 [11] 。
如果数组长度为N,目标sum(即总和的一半)是M,由于全部是正整数,那么在递推过程中涉及到的和只可能是0到M,于是可以用一个 N x (M+1) 的表格tab记录结果。其中tab[i][j]表示在第0至i个数中,是否存在和为j的子集。时间复杂度为O(MN),因为每次递推只需要用到上一行的结果,则空间复杂度可以优化到O(M)...
nums, returnif you can partition the array into two subsets such that the sum of the elements in both subsets is equal orfalseotherwise. Example 1: Input:nums = [1,5,11,5]Output:trueExplanation:The array can be partitioned as [1, 5, 5] and [11]. ...
Can you solve this real interview question? Partition Array Into Three Parts With Equal Sum - Given an array of integers arr, return true if we can partition the array into three non-empty parts with equal sums. Formally, we can partition the array if w
Leetcode每日一题:416.partition-equal-subset-sum(分割等和子集),思路:这题从动态规划的思想上来看很像0-1背包问题,后者需要小于等于背包容量的条件下价值最大化,这里则是刚好等于数组之和的一半;1°,要想满足条件,数组之和sum必须为偶数,并且目标值target=sum/