"type":"mapper_parsing_exception","reason":"Failed to parse mapping [_doc]: For input string: \"NULL\"","caused_by":{"type":"number_format_exception","reason":"For input string: \"NULL\""}},"status":400}
"type": "mapper_parsing_exception", "reason": "Failed to parse mapping [_doc]: For input string: \"null\"" } ], "type": "mapper_parsing_exception", "reason": "Failed to parse mapping [_doc]: For input string: \"null\"", "caused_by": { "type": "number_format_exception", ...
"type":"illegal_argument_exception","reason":"unable to convert [S123456] to long","caused_by":{"type":"number_format_exception","reason":"For input string: \"S123456\""}
"type":"illegal_argument_exception","reason":"Failed to parse int parameter [size] with value [surprise_me]","caused_by":{"type":"number_format_exception","reason":"For input string: \"surprise_me\""}},"status":400}
"reason": "For input string: \"php\"" } }, "status": 400 } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 14. 15. 16. 17. 也能说明以第一次为主以字段第一次的值类型为准。这也说明了默认创建mapping可能不是我们想要的,这就需要手动创建mapping,好处有: ...
"org.elasticsearch" % "elasticsearch-spark_2.11" % "2.3.0" [error] (run-main-0) java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) pattern - For input string: " S" java.lang.IllegalArgumentException: URLDecoder: Illegal hex characters in escape (%) patter...
注意: 在没有创建库的时候搜索,ES会创建一个库并自动创建该字段并且设置为String类型也就是text 什么是elasticsearch? 一个开源的分布式搜索引擎,可以用来实现搜索、日志统计、分析、系统监控等功能 什么是elastic stack(ELK)? 是以elasticsearch为核心的技术栈,包括beats、Logstash、kibana、elasticsearch ...
prop.load(new FileInputStream(file.toFile())); logger.info("[===]jdbc-reload.properties"); for(Object key : prop.keySet()) { logger.info("[===]" + key + "=" + prop.getProperty(String.valueOf(key))); } logger.info("[==...
{\n" + " \"value\": \"java\"\n" + " }\n" + " }\n" + " }\n" + "}"; out.write(params.getBytes()); if (con.getResponseCode() == 200) { BufferedReader br = new BufferedReader(new InputStreamReader(con.getInputStream())); String str = null; while ((str = br....
def last = input.doc.last_name.0; return first + ”” + last; #强类型(10 倍速度于上面的动态类型) String first = (String)((List)((Map)input.get(“doc”)).get(“first_name”)).get(0); String last = (String)((List)((Map)input.get(“doc...