1. I want to duplicate this list of numbers. In Python, I can use the slicing method to achieve it. It's as simple as list1 = [1, 2, 3]; list2 = list1[:]. It's like making a copy of a drawing. 我想要复制这个数字列表。在Python中,我可以使用切片方法来实现。就像list1 = [...
Write a Python program to find the first duplicate element in a given array of integers. Return -1 if there are no such elements.Sample Solution:Python Code :def find_first_duplicate(nums): num_set = set() no_duplicate = -1 for i in range(len(nums)): if nums[i] in num_set: re...
python leetcode 日记 --Contains Duplicate --217 题目 Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Subscribe to see which ...
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 原题地址:Contains Duplicate 难度:Easy 题意:判断数组中是否存在重复的数 思路1: ...
Python Code: # Define a function 'unique_list' that removes duplicates from a listdefunique_list(l):# Create an empty list 'temp' to store unique elementstemp=[]# Iterate through the elements of the input list 'l'forxinl:# Check if the element 'x' is not in the 'temp' list (i....
This should work. I also tweaked your loop a little bit so that the inner loop starts at i instead of 1, and you should remove the element at j. This will keep the first item that you see, and remove any after it.Dim i, j As IntegerFor i = 0 To ListBox1.Items.Count - 2 ...
There is only one duplicate number in the array, but it could be repeated more than once 非常好的题目,开始是用二分做的,比如取数组为{1,2,3,3,4,5},mid应该是(5+1)/2 = 3,那么,如果小于等于mid的数的个数如果超过了3,那么重复的数字一定出现在l,mid之间,否则出现在mid + 1,r之间。以该...
但还是收到了很多没有理解的反馈，主要是根据前文给出的线索去跟踪，是获得到了回滚的标示和异常，而...
Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. class Solution(object): ...
Approach #3: Python. classSolution(object):defcontainsDuplicate(self,nums):""" :type nums: List[int] :rtype: bool """returnlen(nums)!=len(set(nums)) 1. 2. 3. 4. 5. 6. 7. 永远渴望,大智若愚(stay hungry, stay foolish)