leetcode 217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. classSolution(object):defcontainsDuplicate(self, n...
1classSolution {2func longestDupSubstring(_ S: String) ->String {3varsa:[Int] = suffixArray(Array(S),26)4let n:Int =S.count5varlcp:[Int] =buildLCP(Array(S), sa)6varisa:[Int] = [Int](repeating:0,count:n)7foriin0..<n {isa[sa[i]] =i}8varmax:Int =09vararg:Int = -110...
1publicclassSolution {2publicString removeDuplicateLetters(String s) {3if(s==null|| s.length()==0)return"";4Stack<Character> st =newStack<Character>();5StringBuffer sb =newStringBuffer();6boolean[] visited =newboolean[26];7int[] count =newint[26];89for(inti=0; i<s.length(); i...
【leetcode】316. Remove Duplicate Letters 题目如下: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical o......
Unique/Duplicate String 387. First Unique Character in a String 方法: HashMap 26个字母 将字符串中到字母对应到数字: int freq[] = new int[26]; for(int i = 0; i < s.length(); i++){ freq[s.charAt(i) - 'a'] ++; } 387. First Unique Character in a String...
题目如下: Given a string which contains only lowercase letters, remove duplicate letters so that every letter appear once and only once. You must make sure your result is the smallest in lexicographical o...Leetcode 316. Remove Duplicate Letters Problem: Given a string which contains only lowe...
思想是:维护一个栈Stack<Character> st来存最后的结果,先scan一次input,构造一个字典int[] count,记录每个char出现次数。然后进行第二次scan,用st来存最后在string里的character 这次scan的时候,需要维护一个boolean[] visited, 来记录每个字符是否在当前储存结果的stack里。因为每个字符在结果里只会出现一次,所以如果...
s.erase(remove(s.begin(), s.end(), theCharacterNeedtoRemove), s.end()); 其中remove函数需要使用algorithm库文件。算法复杂度为O(26 * n) = O(n) 1classSolution {2public:3stringremoveDuplicateLetters(strings) {4vector<int> alp(26, -1);5for(inti =0, n = s.size(); i < n; i++...
{16ifgroup.count >1{17result.append(group)18}19}2021returnresult22}2324func parse(info: String) ->[(String, String)] {25varcomponents = info.components(separatedBy:"")26let path =components.removeFirst()2728varresult =[(String, String)]()2930let splitCharSet = CharacterSet(charactersIn:"(...
}privateintfindLetter(String s, StringBuilder res, HashMap<Character, ArrayList<Integer>> hm, ArrayList<Character>reference) {intm = 0;for(inti = 0; i < reference.size(); i++) { m= hm.get(reference.get(i)).get(0);intj = i+1;for(; j < reference.size(); j++) { ...