is None:returnprint(root.val,end=' ')dfs_binary_tree(root.left)dfs_binary_tree(root.right)# 构造二叉树 root=TreeNode(1)root.left=TreeNode(2)root.right=TreeNode(3)root.left.left=TreeNode(4)root.left.right=TreeNode(5)# 二叉树的DFS遍历print("二叉树的DFS遍历结果:")dfs_binary_tree(...
# 二叉树的DFS遍历 def dfs_binary_tree(root): if root is None: return print(root.val, end=' ') dfs_binary_tree(root.left) dfs_binary_tree(root.right) # 构造二叉树 root = TreeNode(1) root.left = TreeNode(2) root.right = TreeNode(3) root.left.left = TreeNode(4) root.left.r...
python代码: class TreeNode: def __init__(self, val=0, left=None, right=None): self.val = val self.left = left self.right = right class Solution: def pseudoPalindromicPaths (self, root: TreeNode): self.ass=[0,0,0,0,0,0,0,0,0,0] #计数路径中数字的个数 self.res=0 #记录符...
class TreeNode: def __init__(self, val): self.val = val self.left, self.right = None, None """ class Solution: """ @param: root: The root of the binary search tree. @param: node: insert this node into the binary search tree @return: The root of the new binary search tree....
1-二叉树遍历 1-1-递归 时间复杂度:O(n),n为节点数,访问每个节点恰好一次。 空间复杂度:空间复杂度:O(h),h为树的高度。最坏情况下需要空间O(n),平均情况为O(logn) # Definition for a binary tree node. # class TreeNode:
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right class Solution: def buildTree(self, preorder: List[int], inorder: List[int]) -> Optional[TreeNode]: ...
Python 代码 复制 class Solution:def levelOrder(self, root):""":type root: TreeNode:rtype: List[List[int]]"""res = [] #嵌套列表,保存最终结果if rootisNone:returnresfromcollections import dequeque = deque([root]) #队列,保存待处理的节点while len(que)!=0:lev = [] #列表,保存该层的节...
Python 代码: classSolution:deflevelOrder(self, root):""" :type root: TreeNode :rtype: List[List[int]] """res = []#嵌套列表,保存最终结果ifrootisNone:returnresfromcollectionsimportdeque que = deque([root])#队列,保存待处理的节点whilelen(que)!=0: ...
python3 解答 代码语言:javascript 代码运行次数:0 运行 AI代码解释 # Definitionfora binary tree node.#classTreeNode:# def__init__(self,x):# self.val=x # self.left=None # self.right=NoneclassSolution:# py3 def__init__(self):self.i=0self.can=True ...
# Definition for a binary tree node. # class TreeNode: # def __init__(self, val=0, left=None, right=None): # self.val = val # self.left = left # self.right = right classSolution: defbuildTree(self, preorder:List[int], inorder:List[int])-> Optional[TreeNode]: ...