1Binary Search Tree Iterator2该 Iterator 算法即 non-recursion 的 inorder traversal,不仅仅适用于 BST,任何 Binary Tree 都可以3• stack 中保存一路走到当前节点的所有节点4• stack.peek() 一直指向 iterator 指向的当前节点5• hasNext() 只需要判断 stack 是否为空6• next() 只需要返回 stack.p...
voiddfs(TreeNoderoot){dfs(root.left);dfs(root.right);visit(root);} 1. 非递归实现二叉树的前序遍历 144. Binary Tree Preorder Traversal (Medium) Leetcode/力扣:https://leetcode-cn.com/problems/binary-tree-preorder-traversal/description/ classSolution{//迭代publicList<Integer>preorderTraversal(Tr...
public List<TreeNode> traversal(TreeNode root) { if (root == null) { return null; } return bfs(root); } private List<TreeNode> bfs(TreeNode root) { int curNum = 1; int nextNum = 0; Queue<TreeNode> queue = new LinkedList<>(); List<TreeNode> res = new ArrayList<>(); queue...
str+("->"+(to_string(root->left->val)));if(root->right)dfs(root->right,str+("->"+(to_string(root->right->val)));}vector<string>binaryTreePaths(TreeNode*root){string str=to_string(root->
* 13 * / \ * 65 5 * / \ \ * 97 25 37 * / /\ / * 22 4 28 32 */publicstaticvoidmain(String[]args){int[]arr={,,0,32,0};BinaryTreetree=newBinaryTree(arr);tree.depthOrderTraversal();tree.levelOrderTraversal();}}
/*** leetcdoe 102: 二叉树的层序遍历, 使用 bfs* @param root*/privatestaticList<List<Integer>> bfsWithBinaryTreeLevelOrderTraversal(Node root) {if (root ==null) {// 根节点为空,说明二叉树不存在,直接返回空数组returnArrays.asList();}// 最终的层序遍历结果List<List<Integer>> result = new ...
*@paramroot*/privatestaticList<List<Integer>>bfsWithBinaryTreeLevelOrderTraversal(Node root) {if(root ==null) {//根节点为空,说明二叉树不存在,直接返回空数组returnArrays.asList(); }//最终的层序遍历结果List<List<Integer>> result =newArrayList<>(); ...
{ node* root = newNode(1); root->left = newNode(2); root->right = newNode(3); root->left->left = newNode(4); root->left->right = newNode(5); cout << "Level Order traversal of binary tree is \n"; printLevelOrder(root); return 0; } // This code is contributed by ...
var preorderTraversal = function (root) { var stack = [] function helper(root) { if (!root) return stack.push(root.val) root.left && helper(root.left) root.right && helper(root.right) } helper(root) return stack } 94: 中序遍历的简单实现 ...
What are the methods to implement Depth-First Search (DFS) for binary trees in Java?Recursive Implementation: DFS can be cleanly implemented using recursion.Stack Usage: Using a stack to simulate the recursive process, manually managing the traversal of nodes.Pre-order Traversal: A type of DFS ...