Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the node is found, delete the node...
root.left = self.deleteNode(root.left, key)# key 在右子树elifroot.val < key: root.right = self.deleteNode(root.right, key)returnrootdefgetMin(self, node: TreeNode):# BST 最左边的是最小值whilenode.left !=None: node = node.leftreturnnode...
When a node is deleted, the binary search property of the tree must be preserved, i.e. that the left subtree of the deleted node must contain only values less than the deleted node, and the right subtree must contain only values greater than the deleted node. Deletion in a binary search...
Given a root node reference of a BST and a key, delete the node with the given key in the BST. Return the root node reference (possibly updated) of the BST. Basically, the deletion can be divided into two stages: Search for a node to remove. If the node is found, delete the node...
Searchfora node to remove. If the node is found, delete the node. Note: Time complexity should be O(height of tree). Example: root= [5,3,6,2,4,null,7] key= 3 5 /\3 6 /\ \2 4 7Given key to delete is3. So we find the node with value 3and delete it. ...
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If the node is found, delete the node. Note: Time complexity should be O(height of tree). Example: root = [5,3,6,2,4,null,7] key = 3 5 / \ 3 6 / \ \ 2 4 7 Given key to delete is 3. So we find the node with value 3 and delete it. ...
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Search for a node to remove. If the node is found, delete the node. Note:Time complexity should be O(height of tree). Example: 代码语言:javascript 代码运行次数:0 root=[5,3,6,2,4,null,7]key=35/\36/\ \247Given key todeleteis3.So we find the nodewithvalue3anddeleteit.One valid...
LeetCode 938. Range Sum of BST 2019-12-12 08:00 − 原题链接在这里:https://leetcode.com/problems/range-sum-of-bst/ 题目: Given the root node of a binary search tree, return the sum of values of all nod... Dylan_Java_NYC 0 490 算法——dfs 判断是否为BST 2019-09-29 21...