Leetcode之 Fraction to Recurring Decimal 题目: Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. E...Mysql数值类型之float,double,decimal 对于小数的表示...
long long quotient = lnumerator / ldenominator; result += to_string(quotient); //给余数乘以10是为了后续计算余数的结果为整数 long long remainder = lnumerator % ldenominator * 10; //如果余数为0,直接返回结果 if (remainder == 0) return result; result += "."; unordered_map<long long, in...
Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. Example 1: Input: numerator = 1, denominator = 2 Output: "0.5" Example 2: Input: numerator = 2, ...
Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. Example 1: Input: numerator = 1, denominator = 2 Output: "0.5" Example 2: Input: numerator = 2, ...
String to Integer(atoi) - Michelle小梦想家 754 4 13:12 App LeetCode in Python 110. Balanced Binary Tree - Michelle小梦想家 1376 3 14:37 App A/B Testing (Part I) - Michelle小梦想家 544 -- 21:18 App A/B Testing - Design Experiment 2.2 (Part V) - Michelle小梦想家 1742 -- 19...
【leetcode】1290. Convert Binary Number in a Linked List to Integer 2019-12-23 09:54 − 题目如下: Given head which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The lin... seyjs 0 508 数据类型 2019-12-15 20...
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166. Fraction to Recurring Decimal 标签(空格分隔): leetcode hashtable medium 题目 Given two integers representing the numerator and denominator of a fraction, return the fraction in string format. If the fractional part is repeating, enclose the repeating part in parentheses. ...
Here is a link to a Java implementation of a solution to the LeetCode problem "Fraction to Recurring Decimal" that can be found on ProgramCreek's website. Solution: Let's divide the problem into two parts. Transform1/0.3intoN/Mformat. ...
res+= to_string(rem /den); rem%=den; }returnres; } }; 小数转分数:不循环小数转分数很简单,乘以10的幂将小数部分去掉即可;无限循环小数转分数分两种:一是循环节从小数点后第一位开始的,比如0.333(3/9-->1/3)...、0.7272(72/99-->8/11)...,循环节当做分子,循环节有几位就拿几个9当做分母再...