The previous output of the Python console shows that we have created a new data object called my_date_days, which shows our input date and time 12 days earlier. Example 2: Get datetime X Months Ago In Example 2, I’ll demonstrate how to create a date and time object that is X month...
print("Current Date Time:",datetime.today()) print("Subtract 6 days:", add_days) print("Subtract 6 months:", add_months) print("Subtract 6 years:", add_years) print("Subtract 6 hours:", add_hours) print("Subtract 6 mins:", add_mins) print("Subtract 6 seconds:", add_seconds) ...
python def subtract_months(date, months): # 计算新的年份和月份 year, month = date.year, date.month - months # 处理年份溢出 if month < 1: year -= (1 - month) // 12 month = 12 + (1 - month) % 12 elif month > 12: year += (month - 1) // 12 month = (month -...
subtract 减法pendulum支持的加减的时间颗粒度:years months days hours minutes seconds同时也支持多个参数>>> dt = pendulum.now() >>> >>> >>> dt.add(years=1) DateTime(2022, 9, 14, 16, 16, 42, 375986, tzinfo=Timezone('Asia/Shanghai')) >>> >>> dt.subtract(years=1) DateTime(2020, ...
("Current Date Time:", datetime.datetime.today()) print("Subtract 6 days:", add_days) print("Subtract 6 months:", add_months) print("Subtract 6 years:", add_years) print("Subtract 6 hours:", add_hours) print("Subtract 6 mins:", add_mins) print("Subtract 6 seconds:", add_...
dt_now = dt_now.add(months=4) print(f'增加4个月,显示时间戳:{dt_now.to_datetime_string()}') #减少2个月 dt_now = dt_now.subtract(months=2) print(f'减少2个月,显示时间戳:{dt_now.to_datetime_string()}') #增加1周 dt_now = dt_now.add(weeks=1) ...
print("Subtract 6 days:", add_days) print("Subtract 6 months:", add_months) print("Subtract 6 years:", add_years) print("Subtract 6 hours:", add_hours) print("Subtract 6 mins:", add_mins) print("Subtract 6 seconds:", add_seconds) ...
(seconds=-6)print("Current Date Time:",datetime.datetime.today())print("Subtract 6 days:",add_days)print("Subtract 6 months:",add_months)print("Subtract 6 years:",add_years)print("Subtract 6 hours:",add_hours)print("Subtract 6 mins:",add_mins)print("Subtract 6 seconds:",add_...
last_month = now.subtract(months=1)# 计算日期范围start_date = pendulum.datetime(2022, 1, 1) end_date = pendulum.datetime(2022, 12, 31) date_range = pendulum.period(start_date, end_date)# 计算时差start_time = pendulum.datetime(2022, 1, 1, 0, 0, 0) ...
=target_month:# gone too farone_month_later-=one_daybreakreturnone_month_laterdefsubtract_one_month(t):"""Return a `datetime.date` or `datetime.datetime` (as given) that isone month later.Note that the resultant day of the month might change if the followingmonth has fewer days:>>> ...