years, months, weeks, days, hours, minutes, seconds, microseconds:相对值,可能是负数,加上(add)或减去(subtract)相对值,使用relativedelta中的相对值对原始的datetime进行相应的算术运算。 year, month, day, hour, minute, second, microsecond:绝对值,加上(add)或减去(subtract)一个绝对值,不是对原始的date...
Python的datetime可以处理2种类型的时间,分别为offset-naive和offset-aware。前者是指没有包含时区信息的时间,后者是指包含时区信息的时间,只有同类型的时间才能进行减法运算和比较。datetime模块的函数在默认情况下都只生成offset-naive类型的datetime对象,例如now()、utcnow()、fromtimestamp()、utcfromtimestamp()和...
5. **subtract()**:从日期和时间中减去时间差。 # 当前时间 current_time = datetime.now() # 创建时间差对象 time_delta = datetime.timedelta(days=1, hours=2, minutes=3, seconds=4) # 添加时间差 new_time = current_time + time_delta # 输出:2023-04-02 14:07:00 # 减去时间差 old_time ...
my_datetime=datetime.datetime(2023,6,20,7,35,18)# Constructing example datetimeprint(my_datetime)# Return example datetime#2023-06-20 07:35:18 Example 1: Get datetime X Days Ago In the first example, I’ll explain how to subtract a specific number of daysfrom our datetime object. For t...
>>> past = pendulum.now().subtract(minutes=2) >>> past.diff_for_humans() >>> ‘2 minutes ago’ >>> delta = past – last_week >>> delta.hours 23 >>> delta.in_words(locale=‘en’) ‘6 days 23 hours 58 minutes’ # Proper handling of datetime normalization ...
sub_mins =datetime.today() + relativedelta(minutes=-6) sub_seconds =datetime.today() + relativedelta(seconds=-6) print("Current Date Time:",datetime.today()) print("Subtract 6 days:", add_days) print("Subtract 6 months:", add_months) ...
fromdatetimeimporttimedelta# 创建一个表示30分钟的timedelta对象delta=timedelta(minutes=30) 1. 2. 3. 4. 使用timedelta进行时间运算 使用timedelta对象可以进行日期和时间的加减运算。通过将timedelta对象与datetime对象相加或相减,可以得到一个新的datetime对象。
>>>fromdatetimeimportdatetime,timedleta>>>now=datetime.now()>>>last=datetime(year=2016,month=3,day=10, hour=8)>>>delta=now-last>>>delta datetime.timedelta(282,47010,328000)>>>last+delta==nowTrue 手动实例化timedelta时,可以传入的参数有:days, seconds, microseconds, milliseconds, minutes, hour...
importdatetimeimportcalendar future=datetime.datetime.utcnow()+datetime.timedelta(minutes=5)print(calendar.timegm(future.timetuple())) Output: 1621069619 10在 Python 中遍历一系列日期 importdatetime start=datetime.datetime.strptime("21-06-2020","%d-%m-%Y")end=datetime.datetime.strptime("05-07-2020"...
dt = pendulum.datetime(2011, 8, 1) dt.diff_for_humans(dt.add(months=1)) # '1 month before' dt.diff_for_humans(dt.subtract(months=1)) # '1 month after' pendulum.now().add(seconds=5).diff_for_humans() # '5 seconds from now' ...